4.22g
1. Work out the equation and balance
2AgNo3 +BaCl2 ---> 2AgCl + Ba(No3)2
2. Work out formula mass of silver nitrate (should = 169.9)
3. Calculate the number of moles by doing moles = mass / formula mass so 5 divided by 169.9 = 0.0294 moles.
4. Check ratio - here the ratio is 2:2 i.e. 2 moles of silver nitrate to 2 moles of silver chloride so the moles will be the same so the moles of silver chloride is also 0.0294
5. Work out the formula mass of AgCl (always ignore big numbers at the start when working out formula mass) = 143.4
6. Work out mass by doing equation moles = mass/formula mass so
mass = moles x formula mass
mass = 0.0294 x 143.4
mass = 4.22g (3sf or 2dp)
Answer:
The answer to your question is 25 grams
Explanation:
Data
half-life = 5730 years
sample = 200 g
after 3 half-lives
Process
Calculate the amount of sample after one, two and three half-lives.
After each half-life, that of sample is half the previous amount.
Number of half-lives Amount of sample
0 200 g
1 100 g
2 50 g
3 25 g
Answer:
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Hey there!
<span>In this case, the equation of Clapeyron is used :
R = 0.082
Volume in liters :
100.0 mL / 1000 => 0.1 L
</span>
P * V = n * R * T
15.0 * 0.1 = 0.500 * 0.082 * T
1.5 = 0.041 * T
T = 1.5 / 0.041
T = 36.5 K
Answer C
Answer:
At high temperatures or in the presence of catalysts, sulfur dioxide reacts with hydrogen sulfide to form elemental sulfur and water. This reaction is exploited in the Claus process, an important industrial method to dispose of hydrogen sulfide.
