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2 years ago

Which law represents the movement of gas through a small hole into an area of lower pressure?

1 answer:

3 0

The law is called Graham's law which states that : Under similar conditions of temperature and pressure, the rate of diffusion of gases are inversely proportional to the square root of their densities.

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(14.1.50) 0.03 mol of helium are enclosed in a cylinder with a piston which maintains a constant pressure in the helium. Initial

icang [17]

Answer:

a) 0.210 j /k

b) 0.032 j/k

Explanation:

Find the attachment for solution

3 0

3 years ago

Using the balanced equation for the next few questions: 4 Fe(s) + 30 (9) - 2Fe2O3(s)

stira [4]

Answer:

0.075 moles of iron oxide would be produced by complete reaction of 0.15 moles of iron.

Explanation:

The balanced reaction is:

4 Fe + 3 O₂ → 2 Fe₂O₃

By reaction stoichiometry (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of moles of each compound participate in the reaction:

Fe: 4 moles
O₂: 3 moles
Fe₂O₃: 2 moles

You can apply the following rule of three: if by stoichiometry 4 moles of Fe produce 2 moles of Fe₂O₃, 0.15 moles of Fe produce how many moles of Fe₂O₃?

$moles of Fe_{2} O_{3} =\frac{0.15 moles of Fe*2 moles of Fe_{2} O_{3} }{4 moles of Fe}$

moles of Fe₂O₃= 0.075

0.075 moles of iron oxide would be produced by complete reaction of 0.15 moles of iron.

5 0

2 years ago

How much energy moves onto the next level, in an energy pyramid

dybincka [34]

10% is normally how it works .
For example like 1,000 is the top the next level would be 100 then the next would be 10

7 0

3 years ago

You have 40 g of a radioisotope. If the half-life of this radioisotope is 4 days, how many grams will remain after 12 days?

anygoal [31]

With reference to radioactive material, half-life is the time required to 50% depletion of initial amount of material.

Given: Initial amount of radioactive material = 40 g
Half life = 4 days.

Therefore, After 4 days, amount of compound left = 40/2 = 20 g
After 8 days, i.e 2 half-life, amount of compound left = 20/2 = 10 g
Finally after 12 days, i.e. 3 half-life, amount of compound left = 10/2 = 5 g

Thus, 5 grams will remain after 12 days

5 0

2 years ago

What precipitate is formed when solutions of aluminum nitrate and calcium chromate are mixed?

Scrat [10]

Answer:

Aluminum chromate, a yellow precipitate.

Explanation:

${ \bf{2Al(NO _{3} ) _{3(aq)}+ 3CaCr _{} O _{4(aq)} → { \orange{Al _{2} (CrO _{4} ) _{3(s)}} +3 Ca(NO _{3}) _{2(aq)} }}}$

7 0

2 years ago