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Anastaziya [24]
3 years ago
15

Which law represents the movement of gas through a small hole into an area of lower pressure?

Chemistry
1 answer:
Ierofanga [76]3 years ago
3 0
The law is called Graham's law which states that : <span>Under similar conditions of temperature and pressure, the rate of diffusion of gases are inversely proportional to the square root of their densities. </span>
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Read 2 more answers
Mg(OH)2 + 2 HBr à MgBr2 + 2 H2O
AnnyKZ [126]

Explanation:

The balanced equation of the reaction is given as;

Mg(OH)2 (s) + 2 HBr (aq) → MgBr2 (aq) + 2 H2O (l)

1. How many grams of MgBr2 will be produced from 18.3 grams of HBr?

From the reaction;

2 mol of HBr produces 1 mol of  MgBr2

Converting to masses using;

Mass = Number of moles * Molar mass

Molar mass of HBr = 80.91 g/mol

Molar mass of MgBr2 = 184.113 g/mol

This means;

(2 * 80.91 = 161.82g) of HBr produces (1 * 184.113 = 184.113g) MgBr2

18.3g would produce x

161.82 = 184.113

18.3 = x

x = (184.113 * 18.3 ) / 161.82 = 20.8 g

2. How many moles of H2O will be produced from 18.3 grams of HBr?

Converting the mass to mol;

Number of moles = Mass / Molar mass = 18.3 / 80.91 = 0.226 mol

From the reaction;

2 mol of HBr produces 2 mol of H2O

0.226 mol would produce x

2 =2

0.226 = x

x = 0.226 * 2 / 2 = 0.226 mol

3. How many grams of Mg(OH)2 are needed to completely react with 18.3 grams of HBr?

From the reaction;

2 mol of HBr reacts with 1 mol of Mg(OH)2

18.3g of HBr =  0.226 mol

2 = 1

0.226 = x

x = 0.226 * 1 /2

x = 0.113 mol

5 0
3 years ago
How many phosphorous atoms are found in three molecules of magnesium phosphate, 3Mg3(PO4)2?
aleksandr82 [10.1K]

Answer: Option (d) is the correct answer.

Explanation:

Since the given formula is 3Mg_{3}(PO_{4})_{2}. According to cross method formula, magnesium has +2 charge so, PO_{4} is multiplied by 2.

Thus, 1 molecule of magnesium phosphate will contain 2 atoms of phosphorus.

Therefore, three molecules of magnesium phosphate contains following number of atoms.

  • Mg = 9
  • P = 6
  • O = 24

Hence, we can conclude that there are 6 atoms of phosphorus in three molecules of magnesium phosphate, 3Mg_{3}(PO_{4})_{2}.

4 0
3 years ago
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