Answer:
The minimum initial speed of the cannon ball is approximately 99.018 m/s
Explanation:
The parameters of the cannon are;
The maximum horizontal distance reached, R = 3,279 ft. ≈ 999.4392 m
The maximum horizontal range, , is given by the following formula;
Where;
u = The initial speed
g = The acceleration due to gravity ≈ 9.81 m/s²
= 999.4392 m
We get;
u = √(g × )
∴ u = √(9.81 m/s² × 999.4392 m) ≈ 99.018 m/s
The minimum initial speed of the cannon ball (just as it leaves the cannon) that is needed for it to reach this distance, in m/s, u ≈ 99.018 m/s.
Answer:
19.2 m/s
Explanation:
The train is moving at 18 m/s and you are walking in the same direction (east) so the speeds are added
18 + 1.2 = 19.2
If you were walking backwards (west) your velocity with respect to the ground would be
18 - 1.2 = 16.8
Answer:
It takes millions sometimes hundreds of millions Explanation:
Answer:
false
Explanation:
since it has seven valence electrons it means it's a non metal and non metals always gain electrons.