First, let's calculate it's value: P(r) = (E² * r) / (r + r )² = E² / (4r) Now to check whether this is a maximum, we can compare it with other values of the function, in points between R = r and the other zeroes of P'(R), which here is R = -r. If P reaches a maximum in R=r, that would mean that (1) we can evaluate P in any point R>r and its value should be less than P(r), you can do this for, e.g. R=2r, which yields P(2r) = (2E²)/(9r), which is obviously smaller than P(r).
Also it means that (2) we can evaluate P in any point R so that -r < R < r, and this value should be smaller than P(r). For example, if we take R to be 0, P(R)=0, which is also smaller than P(r). Thus we have proven that P reaches a maximum in r, with corresponding value E² /(4r).
If you wanted the laser to refract less as it exits the prism, you should increase the wavelength of the light.
<h3>What is
refraction?</h3>
Refraction can be defined as a phenomenon which describes a change (bend) in the path taken by light when it's at surfaces between different transparent materials.
According to the model of light wave, the refraction of light is inversely proportional to its wave. Thus, you should increase the wavelength of light, if you want the laser to refract less as it exits the prism.
Read more on refraction here: brainly.com/question/15838784
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The atomic number is how much space is in a object and the mass number is how much it's filled... if I'm not mistaken...
Answer: 1m/s
Explanation: according to the law of conservation of linear momentum in an isolated system, the momentum of the gun equals that of the bullet.
Mathematically
Mb×Vb = Mg×Vg
Where Mb = mass of bullet = 1/100 = 0.01 kg
Vb = velocity of bullet = 200 m/s
Mg = mass of gun = 2kg
Vg = recoil velocity of gun =?
0.01×200 = 2×Vg
Vg = 0.01×200/2
Vg = 0.01×100
Vg = 1m/s
Answer:
Z = 138.5 Ω
Explanation:
In a series RLC circuit the impedance is
Z =
the capacitive impedance is
X_C = 1 / wC
the inductive impedance is
X_L = wL
in this exercise indicate that C = 50 10⁻³ F, L = 0.3 H and the frequency is f=60 Hz
angular velocity and frequency are related
w = 2π f
w = 2π 60
w = 376.99 rad / s
let's calculate
Z =
Z =
Z = √19179.6
Z = 138.5 Ω