Answer:
4.35 atm
Explanation:
According to the information given;
- Initial volume of the gas, V₁ is 2.50 L
- Initial pressure of the gas is standard pressure P₁, normally 1 atm
- New volume of the gas, V₂ is 575 mL
We are required to determine the new pressure of the gas, P₂ ;
To answer the question, we are going to use the Boyle's law, that relates pressure and volume at constant temperature.
According to Boyle's law;
P₁V₁ = P₂V₂
Therefore, to determine the new pressure, P₂, we rearrange the formula;
New pressure, P₂ = P₁V₁ ÷ V₂
Thus;
P₂ = ( 1 atm × 2.50 L) ÷ 0.575 L
= 4.3478 atm
= 4.35 atm
Therefore, the new pressure of the gas is 4.35 atm
The pressure is directly proportional to temperature (when the pressure decrease the temperature decrease too). Because the air parcel expands so the molecules will not interact with each other as much.
The energy of the particles does not change but the fact that the particles are more spaced out means the parcel is cooler.
so now, the warmer a parcel of air the more water vapor it can hold. so, if a parcel of air cools it's ability to hold water vapor drops and if it drops to a low enough point that is when the water vapor will condense and turn back into liquid water. This is how clouds and precipitation form on the the windward side of the mountain.
Answer:
i = 2.483
Explanation:
The vapour pressure lowering formula is:
Pₐ = Xₐ×P⁰ₐ <em>(1)</em>
For electrolytes:
Pₐ = nH₂O / (nH₂O + inMgCl₂)×P⁰ₐ
Where:
Pₐ is vapor pressure of solution (<em>0.3624atm</em>), nH₂O are moles of water, nMgCl₂ are moles of MgCl₂, i is Van't Hoff Factor, Xₐ is mole fraction of solvent and P⁰ₐ is pressure of pure solvent (<em>0.3804atm</em>)
4.5701g of MgCl₂ are:
4.5701g ₓ (1mol / 95.211g) = 0.048000 moles
43.238g of water are:
43.238g ₓ (1mol / 18.015g) = 2.400 moles
Replacing in (1):
0.3624atm = 2,4mol / (2.4mol + i*0.048mol)×0.3804atm
0.3624atm / 0.3804atm = 2,4mol / (2.4mol + i*0.048mol)
2.4mol + i*0.048mol = 2.4mol / 0.9527
2.4mol + i*0.048mol = 2.5192mol
i*0.048mol = 2.5192mol - 2.4mol
i = 0.1192mol / 0.048mol
<em>i = 2.483</em>
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I hope it helps!
Answer:
Qualitative
Explanation:
I'm not sure if there was another part to the question, but if you are looking at the color of the sand, that is a qualitative observation.
- Quantitative statements involve numbers. (Ex: The house has 4 bedrooms.)
- Qualitative statements describe characteristics. (Ex: The house is blue.)
Answer: The molar mass of the unknown compound is 200 g/mol
Explanation:
Depression in freezing point is given by:
= Depression in freezing point
i= vant hoff factor = 1 (for molecular compound)
= freezing point constant = 
m= molality
Weight of solvent (benzene)= 0.250 kg
Molar mass of solute = M g/mol
Mass of solute = 26.7 g
Thus the molar mass of the unknown compound is 200 g/mol
