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Orlov [11]
3 years ago
7

Now consider the reaction a+2b⇌c for which in the initial mixture qc=[c][a][b]2=387 is the reaction at equilibrium? if not, in w

hich direction will it proceed to reach equilibrium? now consider the reaction
Chemistry
1 answer:
Paul [167]3 years ago
5 0
Solving this chemistry is a little bit hard because the question didn't give some important detailed. 
So first, there are a couple problems with your question. 
We will just need to know which direction will it proceed to reach equilibrium.
Your expression for Kc (and Qc ) for the reaction should be: 
Kc = [C] / [A] [B]^2 
You have not provided a value for Kc, so a value of Qc tells you absolutely nothing. Qc is only valuable in relation to a numerical value for Kc. If Qc = Kc, then the reaction is at equilibrium. If Q < K, the reaction will form more products to reach equilibrium, and if Q > Kc, the reaction will form more reactants.
You might be interested in
Select the name of the element with a condensed ground-state electron configuration of [kr] 5s14d7.
Vilka [71]

elements have equal number of protons and neutrons

the condensed format is when the closest noble gas with the closest electron configuration is given, this closest noble gas atomic number should be lesser than the atoms atomic number

atomic number of Kr is 36

1 electron in 5s subshell and 7 electrons in 4d subshell.

there's a total of 36 + 1 + 7 = 44 electrons

atomic number of the atom is 44

element with atomic number 44 is Ruthenium - Ru

answer is Ru


7 0
3 years ago
Read 2 more answers
How much heat was transferred from 50.0 g of water if the temperature of the water went from 30.0 ° C to 55.0 °? The specific he
Lena [83]

Answer:

Heat transfer = Q = 62341.6 J

Explanation:

Given data:

Heat transfer = ?

Mass of water = 50.0 g

Initial temperature = 30.0°C

Final temperature = 55.0°C

Specific heat capacity of water = 4.184 J/g.K

Solution:

Formula:

Q = m.c. ΔT

Q = amount of heat absorbed or released

m = mass of given substance

c = specific heat capacity of substance

ΔT = change in temperature

ΔT = 55.0°C -  30.0°C

ΔT = 25°C (25+273= 298 K)

Q = 50.0 g × 4.184 J/g.K ×298 K

Q = 62341.6 J

4 0
3 years ago
PLEASE HELP!!! I'll give brainliest answer
ELEN [110]

Answer:

1. MG

2. N

3. F

4. NA

5. O

6. K

3 0
3 years ago
Read 2 more answers
I NEED HELP PLEASE! :)
MrMuchimi

<u>answer</u> 1<u> </u><u>:</u>

Law of conservation of momentum states that

For two or more bodies in an isolated system acting upon each other, their total momentum remains constant unless an external force is applied. Therefore, momentum can neither be created nor destroyed.

<u>answer</u><u> </u><u>2</u><u>:</u><u> </u>

When a substance is provided energy<u> </u>in the form of heat, it's temperature increases. The extent of temperature increase is determined by the heat capacity of the substance. The larger the heat capacity of a substance, the more energy is required to raise its temperature.

When a substance undergoes a FIRST ORDER phase change, its temperature remains constant as long as the phase change remains incomplete. When ice at -10 degrees C is heated, its temperature rises until it reaches 0 degrees C. At that temperature, it starts melting and solid water is converted to liquid water. During this time, all the heat energy provided to the system is USED UP in the process of converting solid to the liquid. Only when all the solid is converted, is the heat used to raise the temperature of the liquid.

This is what results in the flat part of the freezing/melting of condensation/boiling curve. In this flat region, the heat capacity of the substance is infinite. This is the famous "divergence" of the heat capacity during a first order phase transition.

There are certain phase transitions where the heat capacity does not become infinitely large, such as the process of a non-magnetic substance becoming a magnetic substance (when cooled below the so-called Curie temperature).

4 0
3 years ago
Really need help!
WARRIOR [948]
The magnitude of a star as it would appear to a hypothetical observer at a distance of 10 parsecs or 32.6 light-years. This rates how visible celestial bodies are when they are all viewed from the same distance. Luminosity: The brightness of a star in comparison with that of the sun.
7 0
3 years ago
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