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Orlov [11]
3 years ago
7

Now consider the reaction a+2b⇌c for which in the initial mixture qc=[c][a][b]2=387 is the reaction at equilibrium? if not, in w

hich direction will it proceed to reach equilibrium? now consider the reaction
Chemistry
1 answer:
Paul [167]3 years ago
5 0
Solving this chemistry is a little bit hard because the question didn't give some important detailed. 
So first, there are a couple problems with your question. 
We will just need to know which direction will it proceed to reach equilibrium.
Your expression for Kc (and Qc ) for the reaction should be: 
Kc = [C] / [A] [B]^2 
You have not provided a value for Kc, so a value of Qc tells you absolutely nothing. Qc is only valuable in relation to a numerical value for Kc. If Qc = Kc, then the reaction is at equilibrium. If Q < K, the reaction will form more products to reach equilibrium, and if Q > Kc, the reaction will form more reactants.
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Classify these definitions as that of an Arrhenius acid, an Arrhenius base, or other. Arrhenius acid definition Arrhenius base d
stealth61 [152]

Answer:

Explanation:

A substance that produces an excess of hydroxide ion (-OH) in aqueous solution.

       This is an arrhenius Base

According to the arrhenius theory, a base is a substance that combines with water to produce excess hydroxide ions, OH⁻ in an aqeous solution. Examples are :

  • Sodium hydroxide NaOH
  • Potassium hydroxide KOH

A substance that produces an excess of hydrogen ion (H+) in aqueous solution

      This is an arrhenius Acid

An arrhenius acid is a substance that reacts with water to produce excess hydrogen ions in aqueous solutions.

Examples are;

  • Hydrochloric acid HCl
  • Hydroiodic acid HI
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5 0
3 years ago
What is the limiting reactant in the following equation? How much Fe2O3 will be produced if 2.1 g of Fe with 2.1 g of O2?
Verizon [17]

Answer:

Fe is limiting, and it will produce .0188 mols of Fe2O3

Explanation:

after you convert both Fe and O2 to mols by using their molar mass, you see there is less Fe than O2 so that is your limiting reactant. To find the amount of Fe2O3 you devide the limiting reactant by it's coefeciant (4) then multiply it by the products coefficant (2). Let me know if you have any questions

8 0
3 years ago
The reaction between bromine gas and fluorine gas to create bromine monofluoride gas has reached equilibrium. What is the effect
DedPeter [7]

Answer: The reaction between bromine gas and fluorine gas to create bromine monofluoride gas has reached equilibrium. What is the effect of adding more bromine gas to the reaction chamber?

More fluorine gas will be produced.

More bromine gas will be produced.

More bromine monofluoride gas will be produced.

Less bromine monofluoride gas will be produced.

I think it is more bromine monofluoride will be produce

Explanation:

8 0
2 years ago
Name the following compound
const2013 [10]

Answer:

bromine

Explanation:

hoefully this is right

8 0
3 years ago
Read 2 more answers
50 POINTS PLEASE HELP!
Aleks04 [339]

Answer: The molar mass of the gas is 9.878 g/mol.

Explanation:

According to Graham's law, the rate of diffusion is inversely proportional to square root of molar mass of gas.

Rate = \frac{1}{\sqrt{M}}

where,

M = molar mass of gas

As given gas diffuses 1/7 times faster than hydrogen gas. So, its molar mass is calculated as follows.

\frac{R_{1}}{R_{2}} = \sqrt{\frac{M_{2}}{M_{1}}}\\

where,

M_{1} = molar mass of hydrogen gas

M_{2} = molar mass of another given gas

R_{1} = rate of diffusion of hydrogen

R_{2} = rate of diffusion of another given gas = \frac{1}{7}R_{1}

Substitute the values into above formula as follows.

\frac{R_{1}}{R_{2}} = \sqrt{\frac{M_{2}}{M_{1}}}\\\frac{R_{1}}{\frac{1}{7}R_{1}} =  \sqrt{\frac{M_{2}}{2}}\\7 \times 1.414 = M_{2}\\M_{2} = 9.878 g/mol

Thus, we can conclude that the molar mass of the gas is 9.878 g/mol.

7 0
3 years ago
Read 2 more answers
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