For part A. 0.85
For part b. 11.9
Explain
Cost of each track in album A= total cost downloading album a/ total number of track
The problem give us a has 11 trackers and the total cost of download is 9.35 pounds
9.35/11
= 0.85
Now we are given each track cost in album b cost the same as track on A
Cost of each track in album B is 0.85
Now we are given if Jane download album B , B will be 14 tracks
Total cost of downloading is album B= number of tracks in album Bx cost of each track in album B
14x0.85 pound
= 11.9
Answer:
c
Step-by-step explanation:
x²+y²+4x+6y=0
compare with x²+y²+2gx+2fy+c=0
centre is (-g,-f)=(-2,-3)
radius=√(g²+f²-c)=√((-2)²+(-3)²-0)=√13
Answer:
<em>Answer: D. Jake paid his loan in 12 months</em>
Step-by-step explanation:
Jake took out an interest-free loan of $2,401.56 from the bank to buy a car.
Since he has to pay no interest for the loan, the monthly payments are totally used to cover the amount of the loan.
He paid the bank $200.13 each month, thus the total months needed to pay the loan is:

Answer: D. Jake paid his loan in 12 months
Answer:
11 tshirts would cost £106.15
Step-by-step explanation:
67.55 divided by 7 = 9.65
9.65 x 11 = 106.15
Therefore the total would be £106.15.
The length of the KN is 4.4
Step-by-step explanation:
We know from Pythagoras theorem
In a right angle ΔLMN
Base² + perpendicular² = hypotenuse
²
From the properties of triangle we also know that altitudes are ⊥ on the sides they fall.
Hence ∠LKM = ∠NKM = 90
°
Given values-
LM=12
LK=10
Let KN be “s”
⇒LN= LK + KN
⇒LN= 10+x eq 1
Coming to the Δ LKM
⇒LK²+MK²= LM²
⇒MK²= 12²-10²
⇒MK²= 44 eq 2
Now in Δ MKN
⇒MK²+ KN²= MN²
⇒44+s²= MN² eq 3
In Δ LMN
⇒LM²+MN²= LN²
Using the values of MN² and LN² from the previous equations
⇒12² + 44+s²= (10+s)
²
⇒144+44+s²= 100+s²+20s
⇒188+s²= 100+s²+20s cancelling the common term “s²”
⇒20s= 188-100
∴ s= 4.4
Hence the value of KN is 4.4