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Mariulka [41]
3 years ago
13

What is qualitative research?

Physics
2 answers:
Sati [7]3 years ago
4 0

Quality research most commonly refers to the scientific. process encompassing all aspects of study design; in. particular, it pertains to the judgment regarding the match. between the methods and questions, selection of subjects, measurement of outcomes, and protection against.

morpeh [17]3 years ago
3 0

Answer:

Research is "creative and systematic work undertaken to increase the stock of knowledge". It involves the collection, organization, and analysis of information to increase understanding of a topic or issue. A research project may be an expansion on past work in the field.

Explanation:

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The endocrine system consists of: (2 points)
motikmotik

Answer: Glands

Explanation: Glands are the structures of the endocrine system that produce and secrete hormones.

8 0
3 years ago
State the sources of alternating current <br>​
Serga [27]

Answer:

hudroelectricity

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4 0
3 years ago
Read 2 more answers
Welcome to this IE. You may navigate to any page you've seen already using the IE Outline tab on the right. A particle beam is m
Genrish500 [490]

Answer:

the magnitude of a uniform electric field that will stop these protons in a distance of 2 m is 10143.57 V/m or 1.01 × 10⁴ V/m

Explanation:

Given the data in the question;

Kinetic energy of each proton that makes up the beam = 3.25 × 10⁻¹⁵ J

Mass of proton = 1.673 × 10⁻²⁷ kg

Charge of proton = 1.602 × 10⁻¹⁹ C

distance d = 2 m

we know that

Kinetic Energy = Charge of proton × Potential difference ΔV

so

Potential difference ΔV = Kinetic Energy / Charge of proton

we substitute

Potential difference ΔV = ( 3.25 × 10⁻¹⁵ ) / ( 1.602 × 10⁻¹⁹ )

Potential difference ΔV = 20287.14 V

Now, the magnitude of a uniform electric field that will stop these protons in a distance of 2 m will be;

E = Potential difference ΔV / distance d

we substitute

E = 20287.14 V / 2 m

E = 10143.57 V/m or 1.01 × 10⁴ V/m

Therefore, the magnitude of a uniform electric field that will stop these protons in a distance of 2 m is 10143.57 V/m or 1.01 × 10⁴ V/m

3 0
3 years ago
Three objects lie in the x, y plane. Each rotates about the z axis with an angular speed of 5.58 rad/s. The mass m of each objec
QveST [7]

Answer:

a) V1=11.05m/s    V2=92.07m/s     V3=17.24m/s

b) KE = 16238.26J

Explanation:

For tangential speeds:

V1 = \omega*R1=5.58*1.98=11.05m/s

V2 = \omega*R2=5.58*16.5=92.07m/s

V3 = \omega*R3=5.58*3.09=17.24m/s

For the kinetic energy, it can be calculated as:

KE=1/2*\omega^2*(I1+I2+I3)

Where:

I1 = m1*R1^2=5.46*1.98^2=21.4kg.m^2

I2 = m2*R2^2=3.64*16.5^2=990.99kg.m^2

I3 = m3*R3^2=3.21*3.09^2=30.65kg.m^2

So,

KE=1/2*5.58^2*(21.4+990.99+30.65)

KE=16238.26J

4 0
3 years ago
A hair dryer draws 11 A when it is connected to 120 V. If electrical energy costs $ 0.09/kW·h, what is the cost of using the hai
Papessa [141]

Answer:

The cost of using the hair dryer for 15 minutes is \$3.6\bar 6

Explanation:

The parameters given in the question are;

The electric current drawn by the the air dryer, I = 11 A

The voltage to which the hair dryer is connected, V = 120 V

The duration of usage of the hair dryer = 15 minutes = 60 minutes /4 = 1 hour/4 = 0.25 hour

The electrical energy costs $0.09/kW·h

The power consumed by the hair dryer = I × V = 11 × 120 = 1320 Watts = 1.32 kW

The energy used by the hair dryer in 15 minutes (0.25 hour) = 1.32 × 0.25 0.33 kW·h

The energy used by the hair dryer in 15 minutes (0.25 hour) = 0.33 kW·h

The energy cost = $0.09/(kW·h)

Therefore;

The cost of using the hair dryer for 15 minutes (0.25 hour) = 0.33 kW·h/($0.09/(kW·h)) = $33/9 = $3 2/3 = $3.6\bar 6.

6 0
3 years ago
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