Hey there!
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An object's velocity can be described by its speed and acceleration.
This statement is true
Hope this helps
Have a great day (:
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The weather report never tells the "humidity" of the air. It tells the
"RELATIVE humidity". That's the percent of the moisture the air
COULD hold at the current temperature that it's actually holding
right now.
If the air is completely dry, then it's holding NONE of the moisture
that it COULD hold, and the relative humidity is zero percent.
Answer:
It allows for transportation and other things
Explanation:
Why are you asking this on the physics section
Answer:
In collision between equal-mass objects, each object experiences the same acceleration, because of equal force exerted on both objects.
Explanation:
In a collision two objects, there is a force exerted on both objects that causes an acceleration of both objects. These forces that act on both objects are equal in magnitude and opposite in direction.
Thus, in collision between equal-mass objects, each object experiences the same acceleration, because of equal force exerted on both objects.
Answer:
a) Fc = 4.15 N, Fi = 435.65 N, (F1)a = 640 N, and F2 = 239.6 N,
b) Ha = 1863.75 N, nfs = 1 , length = 11.8 mm
Explanation:
Given that:
γ= 9.5 kN/m³ = 9500N/m3
b = 6 inches = 0.1524 m
t = 0.0013 mm
d = 2 inches = 0.0508 m
n = 1750 rpm

L = 9 ft = 2.7432 m
Ks = 1.25
g = 9.81 m/s²
a)







b)


dip = 