So what we do is
area that remains=total area-triangle area that was cut out
we need to find 2 things
total area
triangle area
total area=rectange=base times height
area=(3x+4) times (2x+3)
FOIL or distribute
6x^2+8x+9x+12=6x^2+17x+12
triangle area=1/2 times base times height
triangle area=1/2 times (2x+2) times (x-2)=
(x+2) times (x-2)=x^2+2x-2x-4=x^2-4
so
total area=6x^2+17x+12
triangle area=x^2-4
subtract
area that remains=total area-triangle area that was cut out
area that remains=6x^2+17x+12-(x^2-4)=
6x^2+17x+12-x^2+4=
6x^2-x^2+17x+12+4=
5x^2+17x+16
area that remains is 5x^2+17x+16
Answer:
5:56 Pm.
Step-by-step explanation:
I got the answer because i took the driving time and converted into hours and then did the math between times...
The correct answer is D. 11.1
I’m not sure what your teacher wants you to do but I would do 110-50=60
RSU+UST=RST
78+3x-12=6x+12
3x+66=6x+12
3x=54
x=18
108+12=120
∠RST=120°
