Angle m∠1 if formed by a tangent and secant intersecting outside of circle. The intercepted arcs are arc LK and arc JK.
Thus;
Angle formed by Tangent and secant
=1/2(DIFFERENCE of Intercepted Arcs)
m∠1=1/2(mJK-LK)
Answer: m∠1=1/2(mJK-KL)
If we let x and y represent length and width, respectively, then we can write equations according to the problem statement.
.. x = y +2
.. xy = 3(2(x +y)) -1
This can be solved a variety of ways. I find a graphing calculator provides an easy solution: (x, y) = (13, 11).
The length of the rectangle is 13 inches.
The width of the rectangle is 11 inches.
______
Just so you're aware, the problem statement is nonsensical. You cannot compare perimeter (inches) to area (square inches). You can compare their numerical values, but the units are different, so there is no direct comparison.
Subtract 3n and then divide by 4 and you get n= 4
F(x)=x2+4x-9
F(-4)=-4(2)+4(-4)-9
=-8+(-16)-9
=-24-9
=-42