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otez555 [7]
3 years ago
7

What is the slope of the line on the graph?

Mathematics
2 answers:
lutik1710 [3]3 years ago
7 0

Answer:

the slope is 6/1

Step-by-step explanation:

You count how many units up or down in between points (the black dots) and then how many left or right. In this case I went from (0,-1) and went up 6, then right 1. So the slope would be 6/1.

Hope this helps :)

Klio2033 [76]3 years ago
5 0
12/2 or 6/1 should be your answer
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Slope -3/8y+-3/4x=12
grandymaker [24]

Answer:

=

10 − 2 7 - 3

Step-by-step explanation:

6 0
2 years ago
Helen has 48 cubic inches of clay to make a solid square right pyramid with a base edge measuring 6 inches. Which is the slant h
Nikitich [7]

Answer: 5 inches


Step-by-step explanation:

Given: Volume of clay = 48 cubic inches

If we make a solid square right pyramid with a base edge a= 6 inches.

Then its base area = a^2=6^2=36\ inches^2

we know that volume of square right pyramid=\frac{1}{3}\times\ a^2h

Therefore, volume of square right pyramid made by all of clay=\frac{1}{3}\times\ a^2h=48 cubic inches

\Rightarrow\frac{1}{3}\times\ (36)\times\ h=48\\\Rightarrow12h=48\\\Rightarrow\ h=4\ inches.....\text{[Divide 12 on both sides]}

Now, slant height l=\sqrt{(\frac{a}{2})^2+h^2}

\\\Rightarrow\ l=\sqrt{3^2+4^2}\\\Rightarrow\ l=\sqrt{9+16}\\\rightarrow\ l=\sqrt{25}\\\Rightarrow\ l=5

The slant height of the pyramid if Helen uses all the clay=5 inches

5 0
3 years ago
Read 2 more answers
What is the area of the following circle?
zhannawk [14.2K]

Answer:

38.47 m2

Step-by-step explanation:

Area = 3.5 x 3.5 x 3.14

Area = 12.25 x 3.14

Area = 38.465 --> 38.47m2

Hope that helps!

3 0
3 years ago
Read 2 more answers
Plz help fast will mark the brainiest!!!
tiny-mole [99]
3x10^-6 is the answer
3 0
2 years ago
For the function f(x) = –5x, which ordered pair will be a point on the graph of the function?
Drupady [299]
It's D: (0,0)
This is because when you put 0 in for x your y value will equal 0 and that is one of your answers, so it's the point (0,0) 
8 0
2 years ago
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