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Oxana [17]
3 years ago
13

The Baltimore Zoo feeds their elephants a combination of fruit and grass. The zookeeper would like to create a model to represen

t how much food the elephants eat. Each morning, the zookeeper puts out 22 pounds of fruity and an additional 30 pounds of grass per elephant.
Which of the following models the linear relationship between the total weight of elephant food, f(x), based on the number of elephants, x? Select all that apply.

Mathematics
1 answer:
Anika [276]3 years ago
4 0

A function can be represented on a table and on a graph.

The models of the linear relationship between f(x) and x are:

\mathbf{A.\ f(x) = 30x + 22}\\\mathbf{C.\ The\ table}\\\mathbf{F.\ The\ graph}

The given parameters are:

\mathbf{Start = 22}

\mathbf{Additional = 30}

So, the function that models the linear relationship is:

\mathbf{f(x) = Start + Additional \times x}

Substitute known values

\mathbf{f(x) = 22 + 30 \times x}

Evaluate all products

\mathbf{f(x) = 22 + 30x}

Rewrite as:

\mathbf{f(x) = 30x + 22}

By comparing the above function to the list of options, we have the true options to be:

\mathbf{A.\ f(x) = 30x + 22}\\\mathbf{C.\ The\ table}\\\mathbf{F.\ The\ graph}

Read more about linear functions at:

brainly.com/question/20286983

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Answer:

  (a)  positive and increasing

Step-by-step explanation:

Point c is on the x-axis, and point d is above it. The curve between points c and d is positive and increasing.

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According to the synthetic division below, which of the following statements are true? Check all that apply.
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Correct answer just took the quiz

Step-by-step explanation:

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3 years ago
A)A cuboid with a square x cm and height 2xcm². Given total surface area of the cuboid is 129.6cm² and x increased at 0.01cms-¹.
Nutka1998 [239]

Answer: (given assumed typo corrections)


(V ∘ X)'(t) = 0.06(0.01t+3.6)^2 cm^3/sec.


The rate of change of the volume of the cuboid in change of volume per change in seconds, after t seconds. Not a constant, for good reason.



Part B) y'(x+Δx/2)×Δx gives exactly the same as y(x+Δx)-y(x), 0.3808, since y is quadratic in x so y' is linear in x.


Step-by-step explanation:

This problem has typos. Assuming:

Cuboid has square [base with side] X cm and height 2X cm [not cm^2]. Total surface area of cuboid is 129.6 cm^2, and X [is] increas[ing] at rate 0.01 cm/sec.


129.6 cm^2 = 2(base cm^2) + 4(side cm^2)

= 2(X cm)^2 + 4(X cm)(2X cm)

= (2X^2 + 8X^2)cm^2

= 10X^2 cm^2

X^2 cm^2 = 129.6/10 = 12.96 cm^2

X cm = √12.96 cm = 3.6 cm


so X(t) = (0.01cm/sec)(t sec) + 3.6 cm, or, omitting units,

X(t) = 0.01t + 3.6

= the length parameter after t seconds, in cm.


V(X) = 2X^3 cm^3

= the volume when the length parameter is X.


dV(X(t))/dt = (dV(X)/dX)(X(t)) × dX(t)/dt

that is, (V ∘ X)'(t) = V'(X(t)) × X'(t) chain rule


V'(X) = 6X^2 cm^3/cm

= the rate of change of volume per change in length parameter when the length parameter is X, units cm^3/cm. Not a constant (why?).


X'(t) = 0.01 cm/sec

= the rate of change of length parameter per change in time parameter, after t seconds, units cm/sec.

V(X(t)) = (V ∘ X)(t) = 2(0.01t+3.6)^3 cm^3

= the volume after t seconds, in cm^3

V'(X(t)) = 6(0.01t+3.6)^2 cm^2

= the rate of change of volume per change in length parameter, after t seconds, in units cm^3/cm.

(V ∘ X)'(t) = ( 6(0.01t+3.6)^2 cm^3/cm )(0.01 cm/sec) = 0.06(0.01t+3.6)^2 cm^3/sec

= the rate of change of the volume per change in time, in cm^3/sec, after t seconds.


Problem to ponder: why is (V ∘ X)'(t) not a constant? Does the change in volume of a cube per change in side length depend on the side length?


Question part b)


Given y=2x²+3x, use differentiation to find small change in y when x increased from 4 to 4.02.


This is a little ambiguous, but "use differentiation" suggests that we want y'(4.02) yunit per xunit, rather than Δy/Δx = (y(4.02)-y(4))/(0.02).


Neither of those make much sense, so I think we are to estimate Δy given x and Δx, without evaluating y(x) at all.

Then we want y'(x+Δx/2)×Δx


y(x) = 2x^2 + 3x

y'(x) = 4x + 3


y(4) = 44

y(4.02) = 44.3808

Δy = 0.3808

Δy/Δx = (0.3808)/(0.02) = 19.04


y'(4) = 19

y'(4.01) = 19.04

y'(4.02) = 19.08


Estimate Δy = (y(x+Δx)-y(x)/Δx without evaluating y() at all, using only y'(x), given x = 4, Δx = 0.02.


y'(x+Δx/2)×Δx = y'(4.01)×0.02 = 19.04×0.02 = 0.3808.


In this case, where y is quadratic in x, this method gives Δy exactly.

6 0
4 years ago
Zx and Zy<br> are<br> supplementary angles. Zy measures 97°.<br> What is the measure of Zx?
Zinaida [17]

Answer:

83 i think. I learned this a while ago so it might be wrong but i believe supplementary angles add to 180 and complementary add to 360 :)

Step-by-step explanation:

3 0
3 years ago
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