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professor190 [17]
2 years ago
12

Solve. 54.67 / 18.872 x 5.33

Chemistry
1 answer:
alexdok [17]2 years ago
7 0
I believe it’s 15.44
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The following reaction has an equilibrium constant (Keq) of 1 under standard conditions and can be catalysed by the enzyme aspar
Trava [24]

Answer:

  1. What is the AGⓇ of this reaction? 0.
  2. Which will be favoured - the forward reaction, the reverse reaction, or neither? Neither.
  3. What effect does the presence of the enzyme aspartate transaminase have on the Key value when compared with its value in the absence of enzyme? It does not affect the value of Keq.
  4. If one of the products of reaction 1, oxaloacetate, is removed by converting it to citrate as follows: Reaction 2: oxaloacetate + acetyl-CoA citrate + COASH will the key for Reaction l be changed? No, the Keq does not change.

Explanation:

1. To calculate the delta G of a reaction given the K, we use the following equation:

ΔG°= -RT ln K.

Which gives us 0 when K is 1.

2.None of the reactions is favoured. Given that the K equals 1, the system will try to keep the concentration of both products and reagents the same.

3. A catalyst is a substance that, when added, provides a different and faster mechanism through which a reaction takes place. This only means that the speed at which the equilibrium is attained is reduced, but the enzyme does nothing to alter the difference in energy (ΔG°) of the start and end points of the reaction, which ultimately gives us the value of Keq.

4. The addition of a side reaction does not change the value of Keq for the main reaction. They are both separate ways of making oxaloacetate disappear. While the Keq does not change, keep in mind that the end concentrations will not be the same, for any set of starting concentrations of your substances.

4 0
2 years ago
Lee and some other students working with Dr. Yung were conducting an experiment and ended up with some confusing results. In the
Alinara [238K]

Answer:

chung long

Explanation:

cause 3 plus 2 =9

6 0
3 years ago
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Which of the following is NOT true of white dwarfs?
liq [111]

Answer:

A white dwarf is what stars like the Sun become after they have exhausted their nuclear fuel. Near the end of its nuclear burning stage, this type of star expels most of its outer material, creating a planetary nebula. Only the hot core of the star remains. ... That means a white dwarf is 200,000 times as dense.

Explanation:

they are cold

they are about the size of Earth

these both are not true

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3 years ago
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At what point on the hill will the car have zero gravitational potential energy? A) Half-way down the hill. B) At the top of the
kompoz [17]

I think it’s c cause height is what determines gravitational potential energy

3 0
2 years ago
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An airplane starts at rest and Excelerator down the runway for 20 seconds. At the end of the runway, its velocity is 80 m/s Nort
masha68 [24]
According to the formula you have given us to work with . . .

1). The airplane's acceleration is

(80 m/s north - zero) / (20 sec) = 4 m/sec^2 north

2).  For the cyclist:

                                          (V-final - zero) / 20sec = 0.5 m/s^2 south

Multiply each side by 20s :  V-final = 0.5 m/s^2 south x (20sec) = 

                                                                                         10 m/s south

8 0
2 years ago
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