Answer:
The final temperature of the system is 27.3°C.
Explanation:
Heat lost by aluminum = 3.99 × 0.91 × (100-T)
= 3.631 (100-T)
Heat gained by water = 10 × 4.184 × (T-21)
= 41.84 (T-21)
As,
Heat gained = Heat loss
or, 3.631(100-T) = 41.84(T-21)
or,363.1 - 3.631 T = 41.84 T - 878.64)
or, (41.84+ 3.631) T = 878.64 +363.1
or T=
or, T = 27.3°C
Hence the final temperature is 27.3°C.
Answer:
The answer to the questions are as follows
Reaction B is 4426.28 times faster than reaction A
(b) Reaction B is faster.
Explanation:
To solve the question we are meant to compare both reactions to see which one is faster
The values of the given activation energies are as follows
For A
Ea = 95.00 kJ mol–1 (22.71 kcal mol–1) and
for B
Ea = 74.20 kJ mol–1 (17.73 kcal mol–1)
T is the same for both reactions and is equal to 298 k
Concentration of both reaction = 1M
The Arrhenius Law is given by
k =
Where
k = rate constant
Ea = activation energy
R = universal gas constant
T = temperature (Kelvin )
A = Arrhenius factor
Therefore
For reaction A, the rate constant k₁ is given by k₁ =
And for B the rate constant k₂ is given by k₂ =
k₁ = A×2.225×10⁻¹⁷
k₂ = A×9.850×10⁻¹⁴
As seen from the above Reaction B is faster than reaction A by (A×9.850×10⁻¹⁴)/(A×2.225×10⁻¹⁷) or 4426.28 times