Question

a person with a mass of 75kg jumps on the trampoline the trampoline creates a fprce of 375n on them what is the acceleration of the person after they leave the trampoline​

Answer 1

Newton's second law allows calculating the response for the person's acceleration while leaving the trampoline is:

            -4.8 m / s²

Newton's second law says that the net force is proportional to the product of the mass and the acceleration of the body

            F = m a

Where the bold letters indicate vectors, F is the force, m the masses and the acceleration

The free body diagram is a diagram of the forces without the details of the body, in the attached we can see the free body diagram for this system

 

               $F_t$ -W = m a

Whera $F_t$ is the trampoline force

Body weight is

                W = mg

We substitute

              $F_t$ - mg = ma

              a =$\frac{F_t - m g}{m}$

Let's calculate

              a = $\frac{375 - 75 \ 9.8 }{75}$

              a = -4.8 m / s²

The negative sign indicates that the acceleration is directed downward.

In conclusion using Newton's second law we can calculate the acceleration of the person while leaving the trampoline is

            -4.8 m / s²

Learn more here:  brainly.com/question/19860811