To develop this problem we will apply the concepts related to the potential energy per unit volume for which we will obtain an energy density relationship that can be related to the electric field. From this formula it will be possible to find the electric field required in the problem. Our values are given as
The potential energy, ![U = 13.0 J](https://tex.z-dn.net/?f=U%20%3D%2013.0%20J)
The volume, ![V = 6.00 mm^3 = 6.00*10^{-9}m^3](https://tex.z-dn.net/?f=V%20%3D%206.00%20mm%5E3%20%3D%206.00%2A10%5E%7B-9%7Dm%5E3)
The potential energy per unit volume is defined as the energy density.
![u = \frac{U}{V}](https://tex.z-dn.net/?f=u%20%3D%20%5Cfrac%7BU%7D%7BV%7D)
![u= \frac{(13.0 J)}{(6.00*10^{-9} m^3)}](https://tex.z-dn.net/?f=u%3D%20%5Cfrac%7B%2813.0%20J%29%7D%7B%286.00%2A10%5E%7B-9%7D%20m%5E3%29%7D)
![u= 2.167109 J/m^3](https://tex.z-dn.net/?f=u%3D%202.167109%20J%2Fm%5E3)
The energy density related with electric field is given by
![u = \frac{1}{2} \epsilon_0 E^2](https://tex.z-dn.net/?f=u%20%3D%20%5Cfrac%7B1%7D%7B2%7D%20%5Cepsilon_0%20E%5E2)
Here, the permitivity of the free space is
![\epsilon_0 = 8.85*10^-{12} C^2/N \cdot m^2](https://tex.z-dn.net/?f=%5Cepsilon_0%20%3D%208.85%2A10%5E-%7B12%7D%20C%5E2%2FN%20%5Ccdot%20m%5E2)
Therefore, rerranging to find the electric field strength we have,
![E = \sqrt{\frac{2u}{\epsilon_0}}](https://tex.z-dn.net/?f=E%20%3D%20%5Csqrt%7B%5Cfrac%7B2u%7D%7B%5Cepsilon_0%7D%7D)
![E = \sqrt{\frac{2(2.167109)}{8.85*10^{-12}}}](https://tex.z-dn.net/?f=E%20%3D%20%5Csqrt%7B%5Cfrac%7B2%282.167109%29%7D%7B8.85%2A10%5E%7B-12%7D%7D%7D)
![E = 2.211010 V/m](https://tex.z-dn.net/?f=E%20%3D%202.211010%20V%2Fm)
Therefore the electric field is 2.21V/m
Yes, it is because gravity is a force of attraction to the center of our planet, Earth. If we drop a pencil, the pencil will go on the floor. Gravity is pulling the pencil down.
Answer:
The object in a uniform motion covers same distances in an equal time period. Objects in a non-uniform motion cover dissimilar distances in an equal time period.
Explanation:
The speed of the object traveling in uniform motion is constant, the actual speed and the average speed of the moving body is same.
This drag force is always opposite to the object's motion, and unlike friction between solid surfaces, the drag force increases as the object moves faster.
First you do the first parenthesis, (1.08 x 10 - 3) and you do it in the order of operations! (parenthesis, exponents, multiplication/division, add/subtract) to get 7.8. Then you take the second parenthesis (9.3 x 10 - 4) and do the same thing to get 89! You then times 7.8 by 89 to get 694.2! If it needs more elaboration just ask ^.^