Explanation :
From the given information, the graph is plotted.
It is given that, a driver is traveling along a straight road at the speed limit of 60 mph. Initially, he was at point A.
After two minutes, she slows at a constant rate to a stop at a stop light. BC shows this part.
Two minutes later, the light turns green and she accelerates at a constant rate back up to the speed limit. CD shows this part.
Three and a half minutes later, she again slows at a constant rate to a stop. DE shows this part.
Hence, this is the required solution.
- The net force acting on the box is 6N
<h3>Explain the concept?</h3>
- The net force on an object is the sum of all the individual forces acting on it.
- If two opposing forces act on an object, the net force is the difference between the two forces.
- When two forces act in the same direction on an object, the net force is the sum of the two forces.
Here the two force 3N and 3N acting on same direction, so
net force = 3N + 3N
= 6N
Forces that are balanced are those that are opposite in direction and equal in size, but here the equal forces acts in same direction so it is unbalanced
To learn more about net force refer to :
brainly.com/question/18038995
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The speed of the earth's surface located at 2/3 of the length of the arc between the pole which measure from the equator is 232.5 m/s.
Solution:
So the givens are, earth's radius = 6.37X10^6m, and the angular distance from the pole is 90 degrees. So 60 degrees is the 2/3.
r = 6.37x10^6 * cos(60) = 3.185x10^6m
since v = wr
v = 7.3x10^-5 * 3.185x10^6
v - 232.5 m/s
Answer:
The velocity of the pin is opposite its acceleration on the way up.
(d) option is correct.
Explanation:
when the juggler throws a bowling pin straight in the air, the acceleration working on the pin is in the downward direction due to the gravitational force of the earth.
According to Newton's Universal Law of Gravitation
''The gravitational force is a force that attracts any objects with mass''
Answer:
u₂ = 3.7 m/s
Explanation:
Here, we use the law of conservation of momentum, as follows:
where,
m₁ = mass of the car = 1250 kg
m₂ = mass of the truck = 2020 kg
u₁ = initial speed of the car before collision = 17.4 m/s
u₂ = initial speed of the tuck before collision = ?
v₁ = final speed of the car after collision = 6.7 m/s
v₂ = final speed of the truck after collision = 10.3 m/s
Therefore,
<u>u₂ = 3.7 m/s</u>
