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rosijanka [135]
3 years ago
8

A 1500 kg car traveling at 80.0 km/h comes to a screeching halt in a time of 4.00 seconds. Calculate the force of friction exper

ienced by the car.​
Physics
1 answer:
amm18123 years ago
7 0

Answer:

F=m x a

(F is force ,M is mass and A is acceleration)

in thisncase the Mass is given but we need to find ou the acceleration

Formula for acceleration-

a=(v - u)/t

(v is final velocity , u is initiatal velocity and t is time)

a = (0 - 80)/4

a= -80/4

a= -20

By substituting the values-

F= m x a

F= 1500 x -20

F=-30000N

Thus the force acted is -30000N

hope this helps

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what does it mean if the coefficient of friction is greater? for example,a coefficient of friction of 0.1 compared to 0.7
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3 0
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8 0
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