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Dmitrij [34]
2 years ago
9

HELP PLS I DONT KNOW THESE STUFF AND THIS SCHOOL KEEP GIVING IT TO ME SOOO

Mathematics
2 answers:
choli [55]2 years ago
8 0
What’s the question
uysha [10]2 years ago
4 0
What? You don’t have the question.
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BEST ANSWER GETS BRAINLIEST, PLZ ANSWER!!!!
Inga [223]

Answer:

they both = 100

Step-by-step explanation:

3 0
3 years ago
A radioactive substance decays at a continuous rate of 12% per year, and 90 mg of the substance is present in the year 2000. (a)
Alla [95]

Answer:

A(t) = 90e^0.12t ;

299 mg

Step-by-step explanation:

General Continous growth rate equation :

A = Pe^rt

A = amount present, t years after year of initial amount.

Here,

P = 90 mg, amount in year 2000

r = rate = 12% = 0.12

t = years after 2000

Therefore,

A is written as ;

A(t) = 90e^0.12t

Amount present in year 2010 ;

t = 2010 - 2000 = 10

A(10) = 90e^0.12(10)

A(10) = 90 * e^1.2

= 90 * 3.3201169

= 298.81052

= 299 mg

5 0
2 years ago
Please help with this! :)
olchik [2.2K]

Answer:

4 and 3 <------- That's the set I believe!

3 0
3 years ago
What’s the answer to -3 + 47 = 5x + 103
Solnce55 [7]

Answer:

-11.8

Step-by-step explanation:

hope this helps!!!:)

6 0
3 years ago
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Two adjacent angles of a rhombus as in the ratio 2:3. Eind all the a angles of the rombus​
Tomtit [17]

Answer:

Let the adjacent angles of the rhombus be 2x and 3x. We know that the sum of the measures of the adjacent angles is equal to 180°. AD = DC = 3 × 36° = 108°. Hence , the angles of the rhombus are 72° , 108° , 72° and 108°.

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
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