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AURORKA [14]
2 years ago
7

_____ and _______ are necessary for rusting.​

Chemistry
2 answers:
Anastaziya [24]2 years ago
3 0

Answer :-

<h3>Water and Air are necessary for rusting .</h3>

Evgen [1.6K]2 years ago
3 0

Answer:

Water and Oxygen are necessary for rusting.

Explanation:

<h2>HOPE IT HELPS U!!!! </h2>
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Name three of the most sensitive parts of your body (Appropriate parts. Ex: finger, wrist, shoulder, etc.)
yKpoI14uk [10]
Inner thigh, eyes, brain
3 0
3 years ago
Consider a 1260-kg automobile clocked by law-enforcement radar at a speed of 85.5 km/h. If the position of the car is known to w
-BARSIC- [3]
The expected speed is v = 85.5 km/h
 v = 85.5 km/h = (85.5 km/h)*(0.2778 (m/s)/(km/h)) = 23.75 m/s

If there is an uncertainty of 2 meters in measuring the position, then within a 1-second time interval:
The lower measurement for the speed is v₁ = 21.75 m/s,
The upper measurement for the speed is v₂ = 25.75 m/s.
The range of variation is
Δv = v₂ - v₁ = 4 m/s

The uncertainty in measuring the speed is
Δv/v = 4/23.75 = 0.1684 = 16.84%

Answer: 16.8%
3 0
3 years ago
How many cubic miles are 8.48E+08 gallons of water? The density of water at ambient conditions is 1.000 g/mL.
Inessa05 [86]

The volume of the water in cubic meter is determined as 3.2 x 10⁶ m³ .

<h3>Weight of one gallon of water</h3>

The weight of 1 gal of water is given as 3785 g

Mass of 8.48 x 10⁸ gal = 3785 x 8.48 x 10⁸ = 3.2 x 10¹² g

<h3>Volume of the water in cubic meters</h3>

Volume = mass/density

Volume = 3.2 x 10¹² g/1 gmL

Volume = 3.2 x 10¹² mL x 10⁻⁶ m³/mL = 3.2 x 10⁶ m³

Thus, the volume of the water in cubic meter is determined as 3.2 x 10⁶ m³ .

Learn more about volume here: brainly.com/question/1972490

#SPJ1

7 0
2 years ago
What begins to happen to radioactive uranium as soon as a mineral containing it crystallizes from magma?
Aleonysh [2.5K]
<span>The radioactive uranium decays into its daughter product, lead. It would do this in magma as well, as nuclear decay depends on forces within the atom, not on the phase of the material in which the atom is a part.</span>
5 0
3 years ago
How many grams of calcium carbonate, CaCO3, contain 48 grams of oxygen atoms?
Tamiku [17]

Answer:

(40 g O) / (15.99943 g O/mol) x (1 mol CaCO3 / 3 mol O) x (100.0875 g CaCO3/mol) =  

83 g CaCO3

So answer D), although three significant digits are not justified.

Your welcome! Please give me brainiest and have a Great day! <3

7 0
3 years ago
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