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zvonat [6]
4 years ago
5

Write three nuclear equations to represent the nuclear decay sequence that begins with the alpha decay of u-235 followed by a be

ta decay of the daughter nuclide and then another alpha decay.
Physics
2 answers:
Arturiano [62]4 years ago
8 0

Answer:

Explanation:

The first nuclear decay that gave of alpha particle

²³⁵₉₂U → ⁴₂He + ²³¹₉₀Th

The first disintegration gave of alpha particle ⁴₂He converting the original ²³⁵U to ²³¹₉₀Th (Thorium).

This Thorium is unstable and gave off a beta particle. Beta particle are know to have a charge of an electron (e-)

²³¹Th → ⁰-₁ e + ²³¹₉₁Pa

Thorium released a beta particle to produce ²³¹₉₁Pa (protoactinum) in the process.

The protoactinum further disintegrated to produce Actinum releasing an alpha particle (⁴₂He) in the process.

²³¹Pa → ⁴₂He + ²²⁷₈₉Ac

The final product of the nuclear decay is Actinum ²²⁷₈₉Ac.

vazorg [7]4 years ago
5 0

Answer:

We know that in the decay process the sum of molecular number as well as molecular weight should be constant.

The following three reaction are as follows

1 .

Alpha decay  of parent nuclide

_{92}^{235}\textrm{U} \rightarrow _{90}^{231}\textrm{Th}+_{2}^{4}\textrm{alpha }

The molecular number of alpha particle is 2 and molecular weight is 4 g/mol.

2.

Beta decay of daughter nuclide

_{90}^{231}\textrm{Th}\rightarrow _{91}^{231}\textrm{Pa}+_{-1}^{0}\textrm{beta}+v

v is the neutrino emission,The charge on the beta particle is zero.

3.

Alpha decay

_{91}^{231}\textrm{Pa}\rightarrow_{89}^{227}\textrm{Pa}+_{2}^{4}\textrm{alpha}

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Which of the following statements is true for ideal gases, but is not always true for real gases?
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Answer:

C. Replacing one gas by another under the same conditions, has no effect on pressure.

Explanation:

Ideal gas:

 A gas is treated as an ideal gas if temperature is high and pressure is low.

Kinetic energy for ideal gas given as

K.E.=\dfrac{3}{2}KT

So when temperature of gas is increases then  Average molecular kinetic energy will also increases.

The size of molecule is negligible as compare to the dimension of container. It mean that volume occupied by molecule is less as compare to the volume of container.

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4 0
3 years ago
A hill is 132 m long and makes an angle of 12.0 degrees with the horizontal. As a 54 kg jogger runs up the hill, how much work d
TEA [102]

Answer:

14523.55J

Explanation:

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W=mgh.................(1)

where m is the mass, g is acceleration due to gravity taken as 9.8m/s^2 and h is the height of the hill.

Since the length of the hill is 132m and it is inclined at 12 degrees to the horizontal, the height is thus given as follows;

h=132sin12^o\\h=27.44m

Substituting this into equation (1) with all other necessary parameters, we obtain the following;

W=54*9.8*27.44\\W=14523.55J

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