3 years ago

Which of these does NOT emit visible light?

Physics

1 answer:

s344n2d4d5 [400]3 years ago

5 0

c the galaxy because on a nice night you cant see the milkly way

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Planet A takes one year to go around the sun at a distance at a distance of one A U.. Planet B is three A U. from the sun. How m

kotykmax [81]

I would take roughly around 3 years

4 0

2 years ago

ILL GIVE BRAINLYEST

lawyer [7]

Answer:

3rd picture straight line going up right

Explanation:

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5 0

3 years ago

A machine runs for 50 seconds with a steady power output of 100 watts. How many joules of work does the

liberstina [14]

Answer:

The answer to your question is when time = 50 s, work = 5000 J

when time = 90 s, work = 9000 J

Explanation:

Data

time = 50 s or 90 s

Power = 100 watts

Power is defined as the rate of work done per unit of time.

Power = Work / time

-Solve for Work

Work = Power x time

-Substitution

Work = 100 x 50

-Result

Work = 5000

2.-When time = 90 s

Work = 100 x 90

-Result

Work = 9000 watts

6 0

2 years ago

A photon with an energy E = 2.12 GeV creates a proton-antiproton pair in which the proton has a kinetic energy of 96.0 MeV. What

Oksanka [162]

Answer:

The kinetic energy of the anti proton is 147.4 MeV.

Explanation:

Given that,

Energy = 2.12 GeV

Kinetic energy = 96.0 MeV

We need to calculate the kinetic energy of the anti proton

Using formula of energy

$E_{photon}=m_{p}c^2+m_{np}c^2+K.E_{p}+K.E_{np}$

We know that,

$m_{p}c^2=m_{np}c^2$

So, $E_{photon}=2mc^2+K.E_{p}+K.E_{np}$

$K.E_{np}=E_{photon}-(2mc^2+K.E_{p})$

Put the value into the formula

$K.E_{np}=2.12\times10^{9}-2\times938.3\times10^{6}-96\times10^{6}$

$K.E_{np}=147.4\ MeV$

Hence, The kinetic energy of the anti proton is 147.4 MeV.

6 0

3 years ago

Which statements about tornadoes are true? Check all that apply.

fgiga [73]

Answer:

The answer is B,C,D

Explanation:

I took the test

8 0

3 years ago

Read 2 more answers