- Solve 2m + n = 2 and 3m - 2n = 3 using substitution.
We can use the substitution method to solve linear equations of this form. Let's solve for m & n.
To solve a pair of equations using substitution, first solve one of the equations for one of the variables. Then substitute the result for that variable in the other equation.
Choose one of the equations and solve it for m by isolating m on the left-hand side of the equal sign.
Subtract n from both sides of the equation.
Divide both sides by 2.
Multiply 1/2 times -n+2.
Substitute 
for m in the other equation, 3m-2n=3.
Multiply 3 times .
Add 
to -2n.
Subtract 3 from both sides of the equation.
Divide both sides of the equation by 
, which is the same as multiplying both sides by the reciprocal of the fraction.
Substitute 0 for n in 
. Because the resulting equation contains only one variable, you can solve for m directly.
The system is now solved.
Answer:
two solutions : (-3;4) and (-5;6)
Step-by-step explanation:
hello :
X²+y²+18x+29=0 ..(1)
X+y=1 ...(2)
by (2) : y = 1 - x
put this value in (1) : x² +(1-x)² +18x+29 = 0
x² +1 +x² -2x+18x +29 =0
2x²+16x +30 = 0
x²+8x+15 =0
delta = b²-4ac a=1 b=8 c = 15
delta = (8)²-4(1)(15)=64-60 =4 = 2²
X1=(-8+2)/2 = - 3
X2=(-8-2)/2 = - 5
case 1 : x = -3 y = 1 - (-3) = 4
case 2 : x = -5 y = 1 - (-5) = 6
Answer:
Step-by-step explanation:
X Y
--------
1 0.50
2 0.25
3 0.13
4 0.06
5 0.03
The LCM is 24.
1/12=2/24
5/8=15/24
Answer:
615
Step-by-step explanation:
