The transformation was a reflection over the line x = -0.5
And the image and preimage can be seen in the graph below.
<h3>
How to identify the preimage and image?</h3>
First, the original vertices are:
L(3, 3)
M(2, 4)
N(-1, 0)
3 vertices means that our figure is a triangle.
Now, the transformed vertices are:
L'(2, -5)
M'(3, -4)
N'(-1, 1)
And the graph of both sets can be seen below.
Now we can try to identify the transformation.
Now, notice that all the points (L, M, N, L', N', M') are equidistant to the horizontal line x = -0.5
This is a clear implication that the transformation was a reflection over the line x = -0.5
If you want to learn more about transformations:
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Hi! I'm pretty sure this is correct so here it goes:
A. 3/6
B. 12 4/6
Answer:
You could use a piece wise function to simulate the speed someone is running at a given time in minutes.
for 
s = 9 mph
for 
s = 0 mph
for 
s = 6 mph
Step-by-step explanation:
I can't do graphs right now but there's an idea
Answer: 0p + 40
Step-by-step explanation:
5p + 30 - 5p + 10
0p + 40
Answer:
d) All of the above
Step-by-step explanation:
A one way analysis of variance (ANOVA) test, is used to test whether there's a significant difference in the mean of 2 or more population or datasets (minimum of 3 in most cases).
In a one way ANOVA the critical value of the test will be a value obtained from the F-distribution.
In a one way ANOVA, if the null hypothesis is rejected, it may still be possible that two or more of the population means are equal.
This one way test is an omnibus test, it only let us know 2 or more group means are statistically different without being specific. Since we mah have 3 or more groups, using post hoc analysis to check, it may still be possible it may still be possible that two or more of the population means are equal.
The degrees of freedom associated with the sum of squares for treatments is equal to one less than the number of populations.
Let's say we are comparing the means of k population. The degree of freedom would be = k - 1
The correct option here is (d).
All of the above
