An elevator accelerates upward at 1.2 m/s 2 . the acceleration of gravity is 9.8 m/s 2 . what is the upward force exerted by the
floor of the elevator on a(n) 62 kg passenger? answer in units of n.
1 answer:
Answer:
Explanation:
Fr= Fn-P
ma=Fn-mg
Fn= m(a+g)
Fn=62(1.2+9.8)
Fn= 682N
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