An elevator accelerates upward at 1.2 m/s 2 . the acceleration of gravity is 9.8 m/s 2 . what is the upward force exerted by the
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Answer:
The answer is given here would be a simplified equation, seeing as there are some missing variables in the question.
<u>F1 = T- 46, 674.656 gm/s² </u>
Explanation:
<em>Note: Once we have the mass of the second object and/or acceleration of the cord, we can solve for the force of the ground acting on the box.</em>
To calculate the force caused by gravity on the basic pulley system we use the following equation:
F2 = M2 x g; where g= gravitational acceleration (a constant equal to 9.8 m/s²). The mass M2 = 10.5 lb = 4762.72g
∴ F2 = 4762.72g x 9.8 m/s²
= 46, 674.656 gm/s² or 46, 674.656 N
But since this F2 is acting in a downlowrd direction, it would be negative.
Tension of the cord, T = Mass, x × acceleration. ( x is in the pulley diagram)
⇒ F1 = T - F2
<u>F1 = T- 46, 674.656 gm/s² </u>
