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3 years ago

The direction of an electric field is always in the direction _______________ would naturally move.

Physics

1 answer:

Masja [62]3 years ago

6 0

Answer:

Im not really sure but Id say weather .

Explanation:

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What is the kinetic energy of a toy truck with a mass of 0.75 kg and a velocity of 4 m/s? (Formula: )

Dvinal [7]

Answer: Option (b) is the correct answer.

Explanation:

Kinetic energy is the energy of an object or particle when it is in motion.

Mathematically, Kinetic energy = $\frac{1}{2}mass \times (velocity)^{2}$

It is given that toy truck has mass = 0.75 kg, and velocity = 4 m/s.

Calculate the kinetic energy as follows.

Kinetic energy = $\frac{1}{2}mass \times (velocity)^{2}$

= $\frac{1}{2}0.75 kg \times (4 m/s)^{2}$

= $\frac{1}{2}0.75 kg \times 16 m^{2}/s^{2}$

= $0.75 kg \times 8 m^{2}/s^{2}$

= $6 kg m^{2}/s^{2}$

or, Kinetic energy = 6 joules

Thus, we can conclude that kinetic energy of toy truck is 6 J.

6 0

4 years ago

Read 2 more answers

How much money can be found in the pockets/purses of the 250 students in a class if no student may carry 2 identical banknotes w

vaieri [72.5K]

The minimum is $1- $5000000

5 0

3 years ago

What’s is the relationship between energy and motion ?

LekaFEV [45]

Motion energy is the sum of potential and kinetic energy in an object that is used to do work.

5 0

3 years ago

For a body to be in SHM, the restoring force must be __________ to displacement from equilibrium.

Ipatiy [6.2K]

Answer:

Proportional

Explanation:

The conditions that must be met to produce SHM are;

-The restoring force must be proportional to the displacement and act opposite to the direction of motion with no drag forces or friction.

- The frequency of oscillation does not depend on the amplitude.

3 0

2 years ago

A fluid is flowing with an average speed of 1.5 m/s through a tube that has a radius of 2.0 mm and is 18 cm long. The drop in pr

Ymorist [56]

Answer:

μ = 0.038 Pa.s

Explanation:

Given that

V= 1.5 m/s

r= 2 mm

L = 18 cm

If we assume that flow inside the tube is laminar ,then the pressure drop ΔP given as

$\Delta P=\dfrac{32\mu LV^2}{d^2}$

$\mu = \dfrac{\Delta P D^2}{LV^2}$

$\mu = \dfrac{967\times 0.004^2}{0.18\times 1.5^2}\ Pa.s$

μ = 0.038 Pa.s

The viscosity of the fluid = 0.038 Pa.s

5 0

4 years ago