Answer:
a) 23.39
b) 44977.08 N
c) 1922.92N
d) 454.31 MPa
e) 8.32 MPa
f)
Explanation:
a) fiber-matrix load ratio:
Let's use the formula :
b & c)
Total load is given as:
Fc = Ff + Fm
46900 = Fm(23.39) + Fm
46900 = 24.39 Fm
Actual load carried by matrix=
= 1922.92N=> answer for option c
Actual load carried by fiber, Ff:
Ff = 46900 - 1922.92
Ff = 44977.08 N => answer option b
d)
Let's find area of fiber, A_f.
Ac = Cross sectional area =300mm²
= 0.3 * 300 = 99 mm²
Area of matrix=
= 0.7 * 300 = 231 mm²
Magnitude of the stress on the fiber phase:
e) Magnitude of the stress on the matrix phase.
f) Strain in fiber =
Strain in matrix =
Composite strain =
Answer:
The stiffness of an axially loaded bar is (EA)/L
The flexibility of an axially loaded bar is L/(EA)
The stiffness of a torsionally loaded round bar is (GJ)/L
The flexibility of a torsionally loaded round bar is L/(GJ)
Explanation:
For axially loaded round bar, ExA measures, what is known as, the axial rigidity of the round bar. "E" is defined as the Young's modulus which is the property of the bar that measures the stiffness of the bar itself and is meausred in Pascals. A is the area of the cross section of the bar. L is the entire length of the bar. Multiple the Young's modulus with the cross sectional area and divide the value by the length which will give the stiffness of the axially loaded bar. The inverse of this equation will give you the flexibility.
For a Torsionally loaded round bar, the formula is a bit different. G is the modulus rigidity of the bar and J is the Torsional constant. GJ is calculated by multiplying the applied torque with the length od the bar and dividing the result by the angle of the twist. Dividing the result by the length will give the stiffness. Inverse of the equation measuring stiffness gives the flexibility
Explanation:
We assume the T flip-flop changes state on the rising edge of the clock input.
The first stage is connected to the clock. The second stage clock is connected to the inverse of the Q output of the first stage, so that when the first stage Q makes a 1 to 0 transition, the second stage changes state.
Answer:
D. A and B
Explanation:
1. The method Console.Write() is an overloaded method in a language like C#.
One of its variations could be as follows;
<em>Console.Write(String format, Object a, Object b).</em>
This contains three parameters and will write the text representation of the specified objects to the standard output stream using the information specified by the format specifier. Parameter 1 is <em>format</em> which is a composite format string representing the format specifier. Parameter 2 is <em>a</em>, which is the first object to be written using <em>format. </em>Parameter 3 is b, which is the second object to be written using <em>format</em>.
2. The method Console.WriteLine() has the same characteristics as Console.Write() above, except that it writes the text representation of the specified objects, followed by current line terminator then to the standard output stream using the information specified by the format specifier.
3. Console.WriteFormat() does not exist, at least not in C# or .NET
Therefore, Console.Write() and Console.WriteLine() have the capacity to display formatted data.
<em>Hope this helps!</em>