![\huge\underline{\underline{\boxed{\mathbb {SOLUTION:}}}}](https://tex.z-dn.net/?f=%5Chuge%5Cunderline%7B%5Cunderline%7B%5Cboxed%7B%5Cmathbb%20%7BSOLUTION%3A%7D%7D%7D%7D)
<h3>Given:</h3>
▪ ![\longrightarrow \sf{\dfrac{2.1 \times {10}^{5} }{7 \times {10}^{ - 2} } }](https://tex.z-dn.net/?f=%5Clongrightarrow%20%5Csf%7B%5Cdfrac%7B2.1%20%5Ctimes%20%20%7B10%7D%5E%7B5%7D%20%7D%7B7%20%5Ctimes%20%20%7B10%7D%5E%7B%20-%202%7D%20%7D%20%7D)
First, rewrite the numerator in such a way that the coefficient 2.1 becomes 21:
![\small\longrightarrow \sf{\dfrac{21 \times {10}^{ - 6} }{7 \times {10}^{2} } }](https://tex.z-dn.net/?f=%5Csmall%5Clongrightarrow%20%5Csf%7B%5Cdfrac%7B21%20%5Ctimes%20%20%7B10%7D%5E%7B%20-%206%7D%20%7D%7B7%20%5Ctimes%20%20%7B10%7D%5E%7B2%7D%20%7D%20%7D)
Divide the coefficient:
![\small\longrightarrow \sf{21 \div 7=3}](https://tex.z-dn.net/?f=%5Csmall%5Clongrightarrow%20%5Csf%7B21%20%5Cdiv%207%3D3%7D)
Divide the base by subtracting the exponents of the base 10.
![\small\longrightarrow \sf{-6(-2) \Longrightarrow -6+2=-4}](https://tex.z-dn.net/?f=%5Csmall%5Clongrightarrow%20%5Csf%7B-6%28-2%29%20%5CLongrightarrow%20-6%2B2%3D-4%7D)
Hence, the quotient of the given expression has a coefficient of 3 and the exponent of the base 10 is -4.
![\small\longrightarrow \sf{3 \times 10^{-4}}](https://tex.z-dn.net/?f=%5Csmall%5Clongrightarrow%20%5Csf%7B3%20%5Ctimes%2010%5E%7B-4%7D%7D)
![\huge\underline{\underline{\boxed{\mathbb {ANSWER:}}}}](https://tex.z-dn.net/?f=%5Chuge%5Cunderline%7B%5Cunderline%7B%5Cboxed%7B%5Cmathbb%20%7BANSWER%3A%7D%7D%7D%7D)
![\large \bm{The \: \: quotient \: \: is \: \: 3 \times {10}^{ - 4} .}](https://tex.z-dn.net/?f=%5Clarge%20%5Cbm%7BThe%20%5C%3A%20%20%5C%3A%20quotient%20%5C%3A%20%20%5C%3A%20is%20%20%5C%3A%20%5C%3A%203%20%5Ctimes%20%20%7B10%7D%5E%7B%20-%204%7D%20.%7D)
=> 4x = 16 - 8
=>4x= 8
=> x= 2
in short the answer is 2
Answer:
Step-by-step explanation:
i mean i would answer it but i cnt see it for some reason?
First, lets do all calculations in kg. 1kg=1000 grams
Lets set 1 cat's mass as x.
Lets set the other cat's mass as y.
1) x+y=11
2) y=x+1.5
Lets plug eq 2 into eq 1.
x+x+1.5=11
2x+1.5=11
2x=9.5
x=4.75 kg
If one cat weighs 4.75 kg, then the other must weigh 6.25 kg.