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stiks02 [169]
2 years ago
9

Find the perimeter of quadrilateral QUAD. Round your answer to the nearest tenth (1 decimal place)

Mathematics
1 answer:
german2 years ago
6 0
6√5+10

Mark brainliest please


Hope this helps
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Find the 11th term in the following geometric sequence.<br> -5,-10,-20,-40
kondaur [170]
-80....each number is double the one before it
5 0
2 years ago
Solve the system by graphing. {-2x=2y-4, 2x-y=-5
Phantasy [73]

x=(2y-4)/-2

x=-y+2

2(-y+2)-y=-5

-2y+4-y=-5

-3y+4=-5

-3y=-9

y=3

x=-y+2

x=-3+2

x=-1

5 0
3 years ago
Can someone help me with this?
baherus [9]

Answer:

18

Step-by-step explanation:

AB = AW + WB

But AW also equals WB because of the bisecting point

x + 6 = 3x

6 = 2x

x = 3

AW = 3 + 6 = 9

WB = 3(3) = 9

9 + 9 = 18°

If my answer is incorrect, pls correct me!

If you like my answer and explanation, mark me as brainliest!

-Chetan K

8 0
2 years ago
Just number 23 super confused
vodka [1.7K]

Answer:

x = -7

Step-by-step explanation:

This is an exponential equation.

\frac{1}{2}^x=128

We need to take log(or ln) of both sides and use logarithm property to solve this.

So, let's take ln of both sides, so we have:

ln(\frac{1}{2}^x)=ln(128)

Now, we will use this property shown below to further simplify:

ln(a^b)=bln(a)

So, we now have:

ln(\frac{1}{2}^x)=ln(128)\\xln(\frac{1}{2})=ln(128)\\x=\frac{ln(128)}{ln(\frac{1}{2})}\\x=-7

The value of x is -7

6 0
3 years ago
Enter the trigonometric equation you would use to solve for x in the following right triangle. Do not solve the equation.
USPshnik [31]

Answer:

x = sine 70° / 8

Step-by-step explanation:

6 0
3 years ago
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