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3 years ago

Line a is parallel to line b, m∠1=2x+44 and m∠ 5=5x+38 Find the value of x.

Mathematics

1 answer:

Mumz [18]3 years ago

8 0

<span>Line a is parallel to line b:
</span><span>m∠1=m∠ 5, because they are correspondent angles, then:
2x+44=5x+38
Solving for x:
2x+44-2x-38=5x+38-2x-38
6=3x
3x=6
Dividing both sides of the equation by 3
3x/3=6/3
x=2

Answer: Third option: 2</span>

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Given: $f(x) = \frac{1}{x-2}$

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A.)Consider

$f(g(x))= f(\frac{2x+1}{x} )$

$f(\frac{2x+1}{x} )=\frac{1}{(\frac{2x+1}{x})-2}$

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$g(\frac{1}{x-2} )= \frac{x }{1}$

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Since, $f(g(x))=g(f(x))=x$

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Since, the function $f(g(x))$ is not defined for $x=0$ .

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3 years ago

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First, you want to combine like terms.

We can see that the one and eleven can go together, so add them together.

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The reason that we made one, and eleven, negative twelve, is because they are both being subtracted from the numbers before that.

6x - 12

We added the 2x, and the 4x together to make 6x.

Another way to write this would be x - 2, because you can simplify it by dividing it by 6.

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The probability that a randomly selected non-defective product is produced by machine B1 is 11.38%.

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Using Bayes' Theorem

P(A|B) = $\frac{P(B|A)P(A)}{P(B)} = \frac{P(B|A)P(A)}{P(B|A)P(A) + P(B|a)P(a)}$

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P(B|A) is probability of event B given event A

P(B|a) is probability of event B not given event A

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Let P(B1) = Probability of machine B1 = 0.3

P(B2) = Probability of machine B2 = 0.2

P(B3) = Probability of machine B3 = 0.5

Let P(D) = Probability of a defective product

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P(B1|N) = $\frac{P(N|B1)P(B1)}{P(N|B1)P(B1) + P(N|B2)P(B2) + (P(N|B3)P(B3)}$ = $\frac{(0.297)(0.3)}{(0.297)(0.3) + (0.994)(0.2) + (0.990)(0.5)}$ = 0.1138

Hence the probability that a non-defective product is produced by machine B1 is 11.38%.

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