X^3 = 216
by taking cubic root for both sides
![\sqrt[3]{x^3} = \sqrt[3]{216}](https://tex.z-dn.net/?f=%20%5Csqrt%5B3%5D%7Bx%5E3%7D%20%3D%20%20%5Csqrt%5B3%5D%7B216%7D%20)
x = 6
Answer:
what grade are you in
Step-by-step explanation:
Well, (m^2-7m-11) ÷ (m-8) = m+1 with a remainder of -3
Answer:

Step-by-step explanation:
The given equation is:

To find the point where this line intersect the y-axis, we put x=0 into the given equation.
When x=0, we have
.
This implies that; y=5.
The y-intercept is (0,5).
Comparing (0,5) to (0,b), we can conclude that; b=5
Answer:
16.17684994
Step-by-step explanation:
First diagonal
x^2 = a^2 + b^2
x^2 = 5^2 + 6^2
x^2 = 61
x ≈ 7.810249676
Second diagonal
x^2 = a^2 + b^2
x^2 = 7.810249676^2 + 3^2
x^2 = 70
x ≈ 8.366600265
Sum of both diagonals
8.366600265 + 7.810249676
= 16.17684994