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3 years ago

The Hubble Space Telescope was launched in:

Physics

2 answers:

Marat540 [252]3 years ago

7 0

Answer:

B. 1990

<h3>Explanation:</h3>

This article is part of the NASA Knows (Grades 5-8) series. The Hubble Space Telescope is a large telescope in space. It was launched into orbit by space shuttle Discovery on April 24, 1990. Hubble orbits about 547 kilometers (340 miles) above Earth.

Ksju [112]3 years ago

3 0

Answer: 1990

Explanation: Wikipedia say “The Hubble Space Telescope (often referred to as HST or Hubble) is a space telescope that was launched into low Earth orbit in 1990 and remains in operation. It was not the first space telescope, but it is one of the largest and most versatile, renowned both as a vital research tool and as a public relations boon for astronomy. The Hubble telescope is named after astronomer Edwin Hubble and is one of NASA's Great Observatories, along with the Compton Gamma Ray Observatory, the Chandra X-ray Observatory, and the Spitzer Space Telescope.”

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Converges light to a focal point.

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3 years ago

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Find the work done when a constant force f = 13 lbs moves a chair from x = 2.4 to x = 4.1 ft. along the x -axis.

Blizzard [7]

The work done in moving the chair from x = 2.4 to x = 4.1 ft using a force of F = 13 lbs is 29.98 J

This is simply defined as the product of force and distance moved in the direction of the force. Mathematically, it can be expressed as

Workdone (Wd) = force (F) × distance (d)

Wd = Fd

<h3>How to convert lb to N</h3>

1 lb = 4.45 N

Therefore,

13 lbs = 13 × 4.45

13 lbs = 57.85 N

<h3>How to determine the distance in m</h3>

Initial distance = 2.4 ft
Final distance = 4.1 ft
Change in distance = 4.1 -2.4 = 1.7 ft

1 ft = 0.3048 m

Therefore,

1.7 ft = 1.7 × 0.3048

1.7 ft = 0.51816 m

<h3>How to determine the workdone</h3>

Force (F) = 57.85 N
Distance (d) = 0.51816 m
Workdone (Wd) =?

Wd = Fd

Wd = 57.85 × 0.51816

Workdone = 29.98 J

Thus, the workdone in moving the chair is 29.98 J

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2 years ago

A house at the bottom of a hill is fed by a full tank of water 5m deep and connected to the house by a pipe that is 110m long at

yawa3891 [41]

Answer:

a) $p=964178.7\ Pa$

b) $h=98.2853\ m$

Explanation:

Given;

depth of the water-tank, $d=5\ m$

length of the pipe, $l=110\ m$

inclination of the pipe from the horizontal, $\theta =58^{\circ}$

Now the effective vertical height of the water column from the free surface of the water to the bottom of the pipe at house:

$h=d+l.\sin\theta$

$h=5+110\sin58$

$h=98.2853\ m$

Now the pressure due to effective water head:

$p=\rho.g.h$

where:

$\rho=$ density of the liquid, here water

$g=$ acceleration due to gravity

$h=$ height of the liquid column

$p=1000\times9.81\times 98.2853$

$p=964178.7\ Pa$

Now the height of water corresponding to this pressure will be the same as the effective water head by the law of conservation of energy.

$h=98.2853\ m$

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3 years ago

two identical 1.00 x 10^-4 C charges have an electric potential energy of 100 J. how far apart are they. (Unit = m)

STALIN [3.7K]

Answer: 0.899

Explanation:

acellus

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3 years ago

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Which of these is a good example of Newton's First Law of inertia

Eddi Din [679]

Answer: The correct option is A.

Explanation:

Inertia is a state of an object or body to maintain its state. It resists any change in its state.

Newton's first law of inertia: When an objects is in state of motion, it will remain its state of motion or if it is in state of rest then it will remain in rest unless it is acted upon by external motion.

In the given options, a ball sits motionless on the ground is good example of Newton's first law motion. No external force is acting in this case.

In options (B), (C) and (D) , the external force is acting.

Therefore, the correct option is A.

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4 years ago

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