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scoundrel [369]
3 years ago
6

1) make c the subject of of the formula v=c/4-5

Mathematics
1 answer:
alisha [4.7K]3 years ago
8 0

Answer:

1)c = -v 2)(q-5)/4

Step-by-step explanation:

v = c/4-5

v = c/-1

c = -v

q-p=3p+5

q = 4p+5

q-5 = 4p

p = (q-5)/4

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Please solve the equation by factorising
Kobotan [32]

Answer:

X= -2/3, 4

Step-by-step explanation:

5 0
3 years ago
The given two-parameter family is a solution of the indicated differential equation on the interval
mr_godi [17]

Answer:

I do 1 option for you as an example, you need to check the leftover by yourself.

Step-by-step explanation:

for d) y(0) = 0 and y'(pi) =0

y(0) = C_1e^0cos(0)+ C_2 e^0 sin(0) = 0 \longrightarrow C_1 = 0

y(x) ' = C_1e^x cos(x) - C_1e^x sin (x) + C_2e^x sin(x) + C_2e^x cos(x)

y(\pi)'=C_1e^\pi cos(\pi)- C_1e^\pi sin(\pi)+ C_2e^\pi sin(\pi) + C_2e^\pi cos (\pi)

Replace C_1 = 0 we have

y'(\pi) = -C_2e^\pi = 0

if and only if C_2 =0

Hence the given solution does not work.

then, d is NOT the correct answer.

3 0
3 years ago
What is an algebraic expression for the following word phrase: "6 times the difference of b and p?"
Marat540 [252]
1. B
2. C
There you go! :)
6 0
4 years ago
Given that y=6-5x which ordered pairs would graph the function that has the domain values shown on the table?
mina [271]

Answer:

option D. (-3,21),(-2,16),(0,6),(1,1),(2,-4)

Step-by-step explanation:

we have

y=6-5x

we know that

To find the values of y substitute each value of x in the equation

so

1) For x=-3

y=6-5(-3)=21

2) For x=-2

y=6-5(-2)=16

3) For x=0

y=6-5(0)=6

4) For x=1

y=6-5(1)=1

5) For x=2

y=6-5(2)=-4

8 0
4 years ago
When x=-2 and y=-1,-x^2-5xy+5y^3 is
kirill115 [55]

Answer:

-19

Step-by-step explanation:

Evaluate -x^2 - 5 x y + 5 y^3 where x = -2 and y = -1:

-x^2 - 5 x y + 5 y^3 = -(-2)^2 - -2 (-5) + (-1)^3×5

(-2)^2 = 4:

-4 - -5 (-2) + 5×(-1)^3

(-1)^3 = -1:

-4 - -5 (-2) + 5×-1

-5 (-2) = 10:

-4 - 10 - 5

-4 - 10 - 5 = -(4 + 10 + 5):

-(4 + 10 + 5)

| 1 | 0

| | 5

+ | | 4

| 1 | 9:

Answer:  -19

5 0
4 years ago
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