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3 years ago

2 find the probability of getting a sum 9 when two dice are thrown simultaneously.

Mathematics

1 answer:

Cloud [144]3 years ago

3 0

Answer:

The answer is 11.1

Step-by-step explanation:

First you need to figure out what all of the possible combinations of the two dice being thrown then divide it by the number of faces on both dice and you get your probability.

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A man dives to a depth of 105 metres below sea level. A submarine is stationed at a depth which is 60 times the depth of the div

maw [93]

Answer:

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Step-by-step explanation:

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3 years ago

One day of the reunion the whole family went to a nearby museum. Since we were a large group, we got a discounted rate and each

8090 [49]

The normal ticket price is : $15

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3 years ago

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Complete the equation for the standard form of the line that has an x-intercept of 3 and a y-intercept of 5.

Ugo [173]

Answer:

5x+3y=15

Step-by-step explanation:

We are given two coordinates (3,0) (0,5)

Start by finding slope

y2-y1/x2-x1= 5-0/0-3= -5/3 this is your slope m.

y=mx+c

y= -5/3x+c (but remember standard line is ax+by=c) so we have to switch sides

5/3x + y=5 (remember standard form has no fraction so multiply by 3 on all sides)

5x+3y=15

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3 years ago

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Plssss help i give brainliest

notka56 [123]

Answer:

Length=2(x-1)

Width=5

Area=length*width = (2(x-1))(5) = (2x-2)(5) = 10x-10

His reasoning is illogical because whether or not an expression has a term that is being subtracted isn't relevant; technically there are an infinite amount of ways to represent a value. Plus you can just compute the expressions and see that they're equal:

6x-2x+4 = 4x+4

4(x-1) = 4x+4

The two expressions are equal because when you compute the expression 4(n+3)-(3+n) , you get 3n+9:

4(n+3)-(3+n) = 4n+12-3-n = 3n+9

The two expressions are equal because when you compute the expression 2(2n-1), you get 4n-2.

2(2n-1) = (2)(2n)+(2)(-1)=4n-2

5(g+14)=(5)(g)+(5)(14)=5g+70

The expressions aren't equal as 5(g+14) equates to 5g+70 and 5g+70≠5g+14.

3 0

3 years ago

The sales of a grocery store had an average of $7,000 per day. The store introduced several advertising campaigns in order to in

Sati [7]

Answer:

a.The advertising campaigns increased the average daily sales.

Step-by-step explanation:

This is a hypothesis test for the population mean.

The claim is that the advertising campaigns increased the average daily sales.

Then, the null and alternative hypothesis are:

$H_0: \mu=7000\\\\H_a:\mu> 7000$

The significance level is 0.05.

The sample has a size n=100.

The sample mean is M=7280.

The standard deviation of the population is known and has a value of σ=1000.

We can calculate the standard error as:

$\sigma_M=\dfrac{\sigma}{\sqrt{n}}=\dfrac{1000}{\sqrt{100}}=100$

Then, we can calculate the z-statistic as:

$z=\dfrac{M-\mu}{\sigma_M}=\dfrac{7280-7000}{100}=\dfrac{280}{100}=2.8$

This test is a right-tailed test, so the P-value for this test is calculated as:

$\text{P-value}=P(z>2.8)=0.0026$

As the P-value (0.0026) is smaller than the significance level (0.05), the effect is significant.

The null hypothesis is rejected.

There is enough evidence to support the claim that the advertising campaigns increased the average daily sales.

7 0

3 years ago