In archery I need to know what is the box plot for sagars scores

1 answer:

6 0

I think you know by now that I strongly encourage everyone to shoot a proper round and whatever the score is, to submit it to our Records Officer, Giles Conn. Think of it as an annual competition (a) to wear him out, and (b) to see if we can altogether, beat last year's tally. Also, for the outdoor season rounds, you can have a go at achieving the St Wilfred trophy. I've won it 3 years running (last year jointly with Terry Skinner), but they wouldn't let me keep it this time, sadly.

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The school marching band has a budget of up to $750 to cover 15 new uniforms and

PolarNik [594]

a. The inequality 15x+300≤750 represents the situation.

b. It means that the band can spend at most $30 on each uniform without exceeding the budget.

Step-by-step explanation:

Given,

Budget = $750

Competition fee = $300

Uniforms to make = 15

Let,

x be the amount for each uniform.

a. Write an inequality to represent this situation.

Uniforms to make * Cost per uniform + Competition ≤ Budget

15x+300 ≤ 750

The inequality 15x+300≤750 represents the situation.

b. Solve the inequality and describe what it means in the situation.

$15x+300\leq 750\\15x+300-300\leq 750-300\\15x\leq 450$

Dividing both sides by 15

$\frac{15x}{15}\leq \frac{450}{15}\\x\leq 30$

It means that the band can spend at most $30 on each uniform without exceeding the budget.

Keywords: inequality, division

Learn more about inequality at:

#LearnwithBrainly

3 0

2 years ago

For each table, determine whether it shows that x and y are proportional.

myrzilka [38]

9514 1404 393

Answer:

1. proportional, 6

2. not proportional

Step-by-step explanation:

Table 1

Each y-value is 6 times the corresponding x-value, so the variables are proportional, and y = 6 times x.

Table 2

The ratios of y to x are 2, 4, 8, so are not the same. The values are not proportional.

8 0

2 years ago

Evaluate the expression. (-3)^-2

Wewaii [24]

$~~(-3)^{-2}\\\\\\=\dfrac 1{(-3)^2}~~~~~~~~~~~~~~~~~~~~~~~~~;\left[k^{-n} = \dfrac 1{k^n},~~~ k \neq 0\right]\\\\\\=\dfrac 1{(-1)^2 \cdot 3^2}\\\\\\=\dfrac 1{1 \times 9}\\\\\\=\dfrac 19$