Total cost of canvas required in making the tent is rupees 79128
<em><u>Solution:
</u></em>
Given:
Height of the cylindrical tent = h = 3.3 m
Diameter of it's base = d = 100m
r = 50 m
<em><u>Curved surface area of cylinder:</u></em>
![C.S.A = 2 \pi rh](https://tex.z-dn.net/?f=C.S.A%20%3D%202%20%5Cpi%20rh)
![C.S.A = 2 \times 3.14 \times 50 \times 3.3 = 1036.2](https://tex.z-dn.net/?f=C.S.A%20%3D%202%20%5Ctimes%203.14%20%5Ctimes%2050%20%5Ctimes%203.3%20%3D%201036.2)
Thus Curved surface area of cylinder = 1036.2 square meter
<em><u>Curved surface area of cone:</u></em>
![C.S.A = \pi rl](https://tex.z-dn.net/?f=C.S.A%20%3D%20%5Cpi%20rl)
![C.S.A = 3.14 \times 50 \times 56.4 = 8854.8](https://tex.z-dn.net/?f=C.S.A%20%3D%203.14%20%5Ctimes%2050%20%5Ctimes%2056.4%20%3D%208854.8)
Thus Curved surface area of cone = 8854.8 square meter
<em><u>Total curved area of tent:</u></em>
⇒ curved area of cone + curved area of cylinder
![\rightarrow 8854.8 + 1036.2=9891](https://tex.z-dn.net/?f=%5Crightarrow%208854.8%20%2B%201036.2%3D9891)
Thus total curved area of tent = 9891 square meter
<em><u>find total cost of canvas required in making the tent:</u></em>
The cost of canvas is 8 rupees per square meter
![\rightarrow \text{total cost } = 9891 \times 8 = 79128](https://tex.z-dn.net/?f=%5Crightarrow%20%5Ctext%7Btotal%20cost%20%7D%20%3D%209891%20%5Ctimes%208%20%3D%2079128)
Thus total cost of canvas required in making the tent is rupees 79128