2 years ago

Please help with this :(

Physics

1 answer:

Angelina_Jolie [31]2 years ago

8 0

Answer:

I'm sorry I don't have a answer but I like your pfp

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A circular loop of wire of cross-sectional area 0.12 m2 consists of 200 turns, each carrying 0.50 A. It is placed in a magnetic

defon

Answer:

0.52 Nm

Explanation:

A = 0.12 m^2, N = 200, i = 0.5 A, B = 0.050 T

Angle between the plane of loop and magnetic field = 30 Degree

Angle between the normal of loop and the magnetic field = 90 - 30 = 60 degree

θ = 60°

Torque = N i A B Sinθ

Torque = 200 x 0.5 x 0.12 x 0.050 x Sin 60

Torque = 0.52 Nm

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3 years ago

Acceleration is rate of change of__?

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Hi!

Acceleration is the rate of change of velocity

Velocity is the rate of speed of an object

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3 years ago

As water vapor rises into the sky it gets cold. As the water cools, water vapor is transformed into liquid water. When water cha

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Answer:

2: Condensation. 4: 1,d; 2,c; 3,a; 4,e;5,b.

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3 years ago

Consider light of wavelengths 400 nm (UV), 550 nm (green, visible), and 900 nm (infrared). What is the energy associated with a

allsm [11]

Answer:

Energy of UV light $=4.95\times 10^{-19}j$

Energy of green light $=3.6\times 10^{-19}j$

Energy of infrared light $=2.2\times 10^{-19}j$

Explanation:

We have given the wavelength of UV light = 400 nm $=400\times 10^{-9}m$ , wavelength of green light = 550 nm and wavelength of infrared = 900 nm

Speed of light $c=3\times 10^8m/sec$

Plank's constant $h=6.6\times 10^{-34}$

Energy of the signal is given by $E=h\nu =h\frac{c}{\lambda }$

So energy of UV light $E=\frac{6.6\times 10^{-34}\times3\times 10^8}{400\times 10^{-9}}=4.95\times 10^{-19}j$

Energy of green light $E=\frac{6.6\times 10^{-34}\times3\times 10^8}{550\times 10^{-9}}=3.6\times 10^{-19}j$

Energy of infrared light $E=\frac{6.6\times 10^{-34}\times3\times 10^8}{900\times 10^{-9}}=2.2\times 10^{-19}j$

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3 years ago

compute the electric field experienced by a test a charge q = +0.08µC from a source charge q = +15µC in a vacuum when the test c

Fudgin [204]

here is your answer hope it's helpful for you thankyou I

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2 years ago