Velocity or speed, thus they refract or bend
Answer:
D
Explanation:
Acceleration has both magnitude and direction. because velocity is vector quantity
average velocity is vector
linear momentum = mass× velocity
therefore it's also vector
force = mass× acceleration
acceleration is vector therefore force also vector
potential energy= mgh
energy in any form is scaler quantity therefore potential energy too is a scaler quantity.
Answer:
0 m/s²
Explanation:
Draw a free body diagram (see attached).
Sum of the forces normal to the incline:
∑F = ma
N − mg cos θ = 0
N = mg cos θ
Sum of the forces parallel to the incline:
∑F = ma
mg sin θ − f = ma
mg sin θ − Nμ = ma
Substituting:
mg sin θ − (mg cos θ) μ = ma
g sin θ − g μ cos θ = a
a = g (sin θ − μ cos θ)
Given that g = 9.8 m/s², θ = 30°, and μ = 1/√3:
a = (9.8 m/s²) (sin 30° − 1/√3 cos 30°)
a = (9.8 m/s²) (1/2 − 1/2)
a = 0 m/s²
The acceleration down the incline is 0 m/s².
Answer:
Velocity, V = 3t²- 28t+6
Displacement, s = t³ - 14t²+6t -8
At t = 5.8 s
s = -249.05 m
v = -55.48 m/s
At t = 12.7 s
s = -141.48 m
v = 134.27 m/s
Explanation:
We have acceleration of a particle is given by a = 6t - 28
Velocity
At t = 0 we have v₀ = 6 m/s
v₀ = 6 = 3 x 0 ²-28 x 0+C
C = 6
So velocity, V = 3t² - 28t+6
Displacement
At t = 0 we have s₀ = -8 m
s₀ = -8 = 0³ + 14 x 0² + 6 x 0 + C
C = -8
So displacement, s = t³ - 14t²+6t -8
At t = 5.8 s
s = 5.8³ - 14 x 5.8²+6 x 5.8 - 8 = -249.05 m
v = 3 x 5.8² - 28 x 5.8 + 6 = -55.48 m/s
At t = 12.7 s
s = 12.7³ - 14 x 12.7²+6 x 12.7 - 8 = -141.48 m
v = 3 x 12.7² - 28 x 12.7 + 6 = 134.27 m/s