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Nuetrik [128]
3 years ago
9

Describe how organisms in the tropical rainforest both depend on and compete for biotic and abiotic factors. In your answer, ide

ntify which factors are biotic and which are abiotic.
Chemistry
1 answer:
nadezda [96]3 years ago
7 0

What are biotic and abiotic factors?

Biotic and abiotic are the two essential factors responsible for shaping the ecosystem. The biotic factors refer to all the living beings present in an ecosystem, and the abiotic factors refer to all the non-living components like physical conditions (temperature, pH, humidity, salinity, sunlight, etc.) and chemical agents (different gases and mineral nutrients present in the air, water, soil, etc.) in an ecosystem. Therefore, both the abiotic and biotic resources affect the survival and reproduction process.

Answer:

Abiotic factors in the tropical rainforest include humidity, soil composition, temperature, and sunlight. A limiting factor in the ecosystem is that canopy layers block sunlight from reaching the forest floor, causing shorter plants to not be able to grow. Biotic factors in the tropical rainforest include orchids, lilies, heliconia, and bromeliads. Tropical rainforests can have various fungi, shrubs, herbs, woody vines, lichens, and mosses. The trees making up the rainforest canopy include the tonka bean wood, teak, rubber, and several species of evergreens and palm trees. This way the organisms in the tropical rainforest both depend on biotic and abiotic factors.

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mars1129 [50]

Molar mass of butane = 12g/mol*4+1g/mol*10=58g/mol

Mass of 2 moles of butane=2mol*58g/mol=116g

2c4h10(g)+13o2(g)->8co2(g)+10h2o(l)

<span>116g                        8 moles</span>

<span>3.20g                           x</span>

 

116g butane/8moles CO2=3.20g butane/x

x=3.20g butane*8moles CO2/116g butane=0.2207moles CO2

T=23°C=296K

PV=nRT

V=nRT/P=0.2207moles*0.082(atm*dm³/(K/mol))*296K/(1atm)=5.36dm³

6 0
3 years ago
Which of the following is not a chemical change?
MaRussiya [10]

Answer:

May be boiling is the answer because all other options are a proper chemical changes.

3 0
3 years ago
A gas cylinder cannot be half filled​
boyakko [2]

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5 0
4 years ago
A 9.000L tank at 27.0°C is filled with 5.29g of sulfur tetrafluoride gas and 15.6g of carbon dioxide gas. You can assume both ga
Colt1911 [192]

Answer:

Mole fraction SF₄: 0,121

Mole fraction CO₂: 0,879

Partial pressure SF₄: 0,134 atm

Partial pressure CO₂: 0,968 atm

Total pressure: 1,102 atm

Explanation:

The moles of sulfur tetrafluoride gas and carbon dioxide gas are:

5,29g SF₄×\frac{1mol}{108,07g}= <em>0,0489 moles SF₄</em>

15,6 CO₂×\frac{1mol}{44,01g}= <em>0,354 moles CO₂</em>

Mole fraction SF₄:

X_{SF_{4}} = \frac{0,0489mol}{0,0489+0,354} = <em>0,121</em>

Mole fraction CO₂:

X_{CO_{2}} = \frac{0,354mol}{0,0489+0,354} = <em>0,879</em>

It is possible to obtain partial pressure of both gases with moles of each gas using:

P = nRT/V

Where n are respective moles, R is gas constant (<em>0,082atmL/molK</em>), T is teemperature (27°C=<em>300,15K</em>), V is volume (<em>9,0000L)</em>

Replacing:

Partial pressure SF₄: <em>0,134atm</em>

Partial pressure CO₂: <em>0,968atm</em>

Now, the sum of the partial pressures is the total pressure in the tank, that means:

Total pressure: 0,134atm + 0,968atm = <em>1,102atm</em>

<em></em>

I hope it helps!

6 0
3 years ago
Never mind wrong question
Leokris [45]
Its okay my friend. you dont need to over stress it.
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3 years ago
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