1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Nuetrik [128]
2 years ago
9

Describe how organisms in the tropical rainforest both depend on and compete for biotic and abiotic factors. In your answer, ide

ntify which factors are biotic and which are abiotic.
Chemistry
1 answer:
nadezda [96]2 years ago
7 0

What are biotic and abiotic factors?

Biotic and abiotic are the two essential factors responsible for shaping the ecosystem. The biotic factors refer to all the living beings present in an ecosystem, and the abiotic factors refer to all the non-living components like physical conditions (temperature, pH, humidity, salinity, sunlight, etc.) and chemical agents (different gases and mineral nutrients present in the air, water, soil, etc.) in an ecosystem. Therefore, both the abiotic and biotic resources affect the survival and reproduction process.

Answer:

Abiotic factors in the tropical rainforest include humidity, soil composition, temperature, and sunlight. A limiting factor in the ecosystem is that canopy layers block sunlight from reaching the forest floor, causing shorter plants to not be able to grow. Biotic factors in the tropical rainforest include orchids, lilies, heliconia, and bromeliads. Tropical rainforests can have various fungi, shrubs, herbs, woody vines, lichens, and mosses. The trees making up the rainforest canopy include the tonka bean wood, teak, rubber, and several species of evergreens and palm trees. This way the organisms in the tropical rainforest both depend on biotic and abiotic factors.

You might be interested in
The edge length of the unit cell of KCl (NaCl-like structure, FCC) is 6.28 Å. Assuming anion-cation contact along the cell edge,
Mila [183]

Answer:

1.33 Å

Explanation:

Given that the edge length , a of the KCl which forms the FCC lattice = 6.28 Å

Also,

For the FCC lattice in which the anion-cation contact along the cell edge , the ratio of the radius of the cation to that of anion is 0.731.

Thus,

\frac {r^+}{r^-}=0.731 .................1

Also, the sum of the radius of the cation and the anion in FCC is equal to half of the edge length.

Thus,

r^++r^-=\frac {a}{2}  ...................2

Given that:

Cl^-\ (r^-) = 1.82\ \dot{A}

To find,

K^+\ (r^+) = ? \dot{A}

Using 1 and 2 , we get:

1.731\ r^+=0.731\times \frac {6.28}{2}

<u>Size of the potassium ion = 1.33 Å</u>

4 0
3 years ago
Hurry and Help for Brainlist
zalisa [80]
Ummm i think it’s solid
3 0
2 years ago
Read 2 more answers
How many moles of carbon dioxide gas should be produced when 10.0 g of C2H6 are combusted at STP?
Finger [1]

Answer:

                    0.665 moles of CO₂

Explanation:

                     The balance chemical equation for the combustion of Ethane is as follow:

                            2 C₂H₆ + 7 O₂ → 4 CO₂ + 6 H₂O

Step 1: <u>Calculate moles of C₂H₆ as;</u>

                              Moles  =  Mass  /  M.Mass

Putting values,

                              Moles  =  10.0 g / 30.07 g/mol

                              Moles  =  0.3325 moles

Step 2: <u>Calculate Moles of CO₂ as;</u>

According to balance chemical equation,

                    2 moles of C₂H₆ produced  =  4 moles of CO₂

So,

             0.3325 moles of C₂H₆ will produce  =  X moles of CO₂

Solving for X,

                      X  =  0.3325 mol × 4 mol ÷ 2 mol

                      X = 0.665 moles of CO₂

3 0
2 years ago
A sample of gas occupies 10.0 L at 240°C under a pressure of
NISA [10]

Answer: 1090°C

Explanation: According to combined gas laws

(P1 × V1) ÷ T1 = (P2 × V2) ÷ T2

where P1 = initial pressure of gas = 80.0 kPa

V1 = initial volume of gas = 10.0 L

T1 = initial temperature of gas = 240 °C = (240 + 273) K = 513 K

P2 = final pressure of gas = 107 kPa

V2 = final volume of gas = 20.0 L

T2 = final temperature of gas

Substituting the values,

(80.0 kPa × 10.0 L) ÷ (513 K) = (107 kPa × 20.0 L) ÷ T2

T2 = 513 K × (107 kPa ÷80.0 kPa) × (20.0 L ÷ 10.0 L)

T2 = 513 K × (1.3375) × (2)

T2 = 1372.275 K

T2 = (1372.275 - 273) °C

T2 = 1099 °C

8 0
3 years ago
Read 2 more answers
A 16.4 g sample of calcium chloride is dissolved in enough water to make 750.0 mL of solution. Calculate the molarity of calcium
EastWind [94]
SIMP FOR LEVI AKRAMEN
7 0
2 years ago
Other questions:
  • Ephedrine, a central nervous system stimulant, is used in nasalsprays as a decongestant. this compound is a weak organic base: {
    6·1 answer
  • The electron domain and molecular geometry of bro2- is __________.
    14·2 answers
  • Which is the first element in the periodic table to have an electron configuration in the 4th energy level? beryllium carbon pot
    12·2 answers
  • Consider the reaction: I2(g)+Cl2(g)⇌2ICl(g) Kp= 81.9 at 25 ∘C. Calculate ΔGrxn for the reaction at 25 ∘C under each condition: -
    11·2 answers
  • Understanding the Cloning Process
    8·2 answers
  • 50 POINTS
    11·2 answers
  • Doraemon part of the water cycle heat from the Sun causes liquid to change into water vapor Which Resident to the atmosphere whi
    5·1 answer
  • What is a Bohr model?
    15·2 answers
  • A small piece of hot metal is placed in cooler water. The metal is left in the water
    6·1 answer
  • I just need the answers I’ve been procrastinating for hours
    9·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!