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vladimir1956 [14]
3 years ago
14

MULTIPLE CHOICE QUESTION

Chemistry
1 answer:
zubka84 [21]3 years ago
4 0

Answer:

This question will be answered based on general understanding of how a controlled experiment should be:

The answer is: We must make sure we are testing/changing only one variable, and controling others

Explanation:

A controlled experiment is an experiment in which the independent variable is changed for a particular group called the EXPERIMENTAL group and unchanged for another group called the CONTROL group.

In a controlled experiment, only one variable should be tested while the others should be kept constant in order to have an effective result or outcome. This is the case in this question, the type of music or soil should be unchanged for each plant because the experimenter must make sure that he/she is testing/changing only one variable, and controling others.

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Which of the following is TRUE?
stiks02 [169]

Answer:

Explanation:

For a general equilibrium

aA +bB ⇔ cC + dD ,

the equilibrium constant is K = [C]^c [D]^d / [A]^a[B]^b.

Our reasoning here should be based on the fact that  Q has the same expression as K, but is used when the system is not at equilibrium, and the system will react to make Q = K to attain it ( Le Chatelier´s principle ).

So with this in mind, lets answer this question.

1. False: Q can large or small but is not the value of the equilibrium constant, it will predict the side towards the equilibrium will shift to attain it.

2. False: Given the expression for the equilibrium constant, we know if K is small the concentrations of the reactants will be large compared to the equilibrium concentrations of the products.

3. False: when the value of K is large, the equilibrium concentrations of the products will be large and it will lie on the product side.

4. True: From our previous reasongs this is the true one.

5. False: If K is small, the equilibrium lies on the reactants side.

8 0
3 years ago
Heat in the amount of 100 kJ is transferred directly from a hot reservoir at 1400 K (TH) to a cold reservoir at 600 K. Calculate
klasskru [66]

Answer:

ΔS = - 0.125 Kj/K decreased entropy

Explanation:

From ΔH = TΔS => ΔS = ΔH/T

= 100Kj/(600K - 1400K) = - 188Kj/800K = - 0.125 Kj/K

Entropy in the cooler flask would have 'decreased' (i.e.; more ordered state) at 600K.

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