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koban [17]
3 years ago
13

I NEED HELP ASAP, IM DOING A MASTERY TEST ON PLATO SJJSNSNSJSJSSN PLEASE AND THANK YOU

Chemistry
2 answers:
mote1985 [20]3 years ago
6 0

Condensation is the process of conversion of a substance present in vapor state to to liquid state. Clouds are formed when water vapor present in air condenses and changes from vapor to liquid state. The fast moving, energetic water molecules present in the vapor state, when encounter a cooler surface slow down during condensation and come closer to form a liquid.

So the correct answer will be,

A. molecules come closer and stick to each other.

Hoochie [10]3 years ago
5 0

Condensation is conversion of vapours to liquid

in vapour the molecules of water are far from each other and can move here and there. When a liquid like water condense the molecules come closer to each other.

Thus come closer together and stick to each other.


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Explanation:

atom changes from a ground state to an excited state by taking on energy from its surroundings in a process called absorption. The electron absorbs the energy and jumps to a higher energy level. In the reverse process, emission, the electron returns to the ground state by releasing the extra energy it absorbed

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What is the identity of the element whose isotopes you have selected
Pachacha [2.7K]

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Rubidium

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5 0
3 years ago
Gaseous ethane will react with gaseous oxygen to produce gaseous carbon dioxide and gaseous water . Suppose 2.7 g of ethane is m
Bond [772]

Answer:

m_{H_2O}=4.86gH_2O

Explanation:

Hello,

In this case, the described chemical reaction is:

C_2H_6+\frac{7}{2} O_2\rightarrow 2CO_2+3H_2O

Thus, for the given reacting masses, we must identify the limiting reactant for us to determine the maximum mass of water that could be produced, therefore, we proceed to compute the available moles of ethane:

n_{C_2H_6}=2.7gC_2H_6*\frac{1molC_2H_6}{30gC_2H_6} =0.09molC_2H_6

Next, we compute the moles of ethane consumed by 13.0 grams of oxygen by using the 1:7/2 molar ratio between them:

n_{C_2H_6}^{consumed\ by \ O_2}=13.0gO_2*\frac{1molO_2}{32gO_2}*\frac{1molC_2H_6}{\frac{7}{2} molO_2}=0.116molC_2H_6

Thus, we notice there are less available moles of ethane, for that reason, it is the limiting reactant, thereby, the maximum amount of water is computed by considering the 1:3 molar ratio between ethane and water:

m_{H_2O}=0.09molC_2H_6*\frac{3molH_2O}{1molC_2H_6} *\frac{18gH_2O}{1molH_2O} \\\\m_{H_2O}=4.86gH_2O

Best regards.

3 0
3 years ago
A compound is found to contain 7.962 % silicon , 20.10 % chlorine , and 71.94 % iodine by mass. to answer the question, enter th
arlik [135]
Empirical   formula  is  calculated   as  follows

calculate  the  moles  of  each  element,  that  is   %  composition/  molar  mass
molar  masses  (  Si=  28.09g/mol ,  Cl=  35.5  g/mol,  I=126.9 g/mol)

moles  of  silicon =  7.962/28.09g/mol=  0.283  moles
moles  of  chlorine =  20.10 / 35.5g/mol =  0.566  moles
moles  of  iodine=  71.94 / 126.9  g/mol=  0.567  moles

divide  each  mole   with  smallest    mole  (0.283)
that  is    silicon =  0.283/0.283= 1 mole
             chlorine =  0.566/0.283=  2 mole
            Iodine=  o.567/0.283= 2  moles
empirical  formula  is  therefore=  SiCl2I2


5 0
3 years ago
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