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koban [17]
3 years ago
13

I NEED HELP ASAP, IM DOING A MASTERY TEST ON PLATO SJJSNSNSJSJSSN PLEASE AND THANK YOU

Chemistry
2 answers:
mote1985 [20]3 years ago
6 0

Condensation is the process of conversion of a substance present in vapor state to to liquid state. Clouds are formed when water vapor present in air condenses and changes from vapor to liquid state. The fast moving, energetic water molecules present in the vapor state, when encounter a cooler surface slow down during condensation and come closer to form a liquid.

So the correct answer will be,

A. molecules come closer and stick to each other.

Hoochie [10]3 years ago
5 0

Condensation is conversion of vapours to liquid

in vapour the molecules of water are far from each other and can move here and there. When a liquid like water condense the molecules come closer to each other.

Thus come closer together and stick to each other.


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Write the formulas for the following compounds :
Vanyuwa [196]
Sodium phosphate = Na₃PO₄

phosphorus triiodide = PI3

hope this helps. make brainliest please!
6 0
3 years ago
Read 2 more answers
Sodium azide, NaN3, the explosive compound found in automobile air bags, decomposes according to the following equation: 2NaN3(s
shutvik [7]

Answer:

1.9 × 10² g NaN₃

1.5 g/L

Explanation:

Step 1: Write the balanced decomposition equation

2 NaN₃(s) ⇒ 2 Na(s) + 3 N₂(g)

Step 2: Calculate the moles of N₂ formed

N₂ occupies a 80.0 L bag at 1.3 atm and 27 °C (300 K). We will calculate the moles of N₂ using the ideal gas equation.

P × V = n × R × T

n = P × V / R × T

n = 1.3 atm × 80.0 L / (0.0821 atm.L/mol.K) × 300 K = 4.2 mol

We can also calculate the mass of nitrogen using the molar mass (M) 28.01 g/mol.

4.2 mol × 28.01 g/mol = 1.2 × 10² g

Step 3: Calculate the mass of NaN₃ needed to form 1.2 × 10² g of N₂

The mass ratio of NaN₃ to N₂ is 130.02:84.03.

1.2 × 10² g N₂ × 130.02 g NaN₃/84.03 g N₂ = 1.9 × 10² g NaN₃

Step 4: Calculate the density of N₂

We will use the following expression.

ρ = P × M / R × T

ρ = 1.3 atm × 28.01 g/mol / (0.0821 atm.L/mol.K) × 300 K = 1.5 g/L

5 0
3 years ago
Describe two ways you think a sound wave could be stopped or could change change direction.
Alla [95]

Answer:

Like any wave, a sound wave doesn't just stop when it reaches the end of the medium or when it encounters an obstacle in its path. Rather, a sound wave will undergo certain behaviors when it encounters the end of the medium or an obstacle. Possible behaviors include reflection off the obstacle, diffraction around the obstacle, and transmission (accompanied by refraction) into the obstacle or new medium

8 0
3 years ago
Read 2 more answers
4. Identify each substance in the following word equation as a reactant or a product
dolphi86 [110]

Explanation:

4.                 limestone heat lime + carbon dioxide

The reactants in this expression above is limestone

The products of the reaction is carbon dioxide and lime

Reactant is the species that gives the product and it is usually found on the left hand side of the expression.

The product is the substance on the right hand side of the expression that forms through the experiment.

Heat is used to facilitate the reaction.

5. An exothermic reaction is a reaction in which heat is given off.

An endothermic reaction is a reaction in which heat is absorbed in the process.

An exothermic reaction is always warmer after the reaction whereas an endothermic reaction is colder at the end of the reaction.

6.  Sodium salicylate is made from carbon dioxide and sodium phenoxide.

The reactants are:

                  Carbon dioxide and sodium phenoxide

The product is:

         Sodium salicylate

8 0
3 years ago
what volume of co2 is produced at stp when 270g of glucose are consumed in the following reaction? c6h12o6 + 6o2(g) -> 6co2 (
lana [24]

Answer:

202 L

Explanation:

Step 1: Write the balanced equation

C₆H₁₂O₆ + 6 O₂(g) ⇒ 6 CO₂(g) + 6 H₂O(l)

Step 2: Calculate the moles corresponding to 270 g of C₆H₁₂O₆

The molar mass of C₆H₁₂O₆ is 180.16 g/mol.

270 g × 1 mol/180.16 g = 1.50 mol

Step 3: Calculate the moles of CO₂ generated from 1.50 moles of glucose

The molar ratio of C₆H₁₂O₆ to CO₂ is 1:6. The moles of CO₂ formed are 6/1 × 1.50 mol = 9.00 mol

Step 4: Calculate the volume of 9.00 moles of CO₂ at STP

The volume of 1 mole of an ideal gas at STP is 22.4 L.

9.00 mol × 22.4 L/mol = 202 L

4 0
3 years ago
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