Answer : The value of
is -49.6 kJ/mol
Explanation :
First we have to calculate the reaction quotient.
Reaction quotient (Q) : It is defined as the measurement of the relative amounts of products and reactants present during a reaction at a particular time.
The given balanced chemical reaction is,

The expression for reaction quotient will be :
![Q=\frac{[ADP][HPO_4^{2-}]}{[ATP]}](https://tex.z-dn.net/?f=Q%3D%5Cfrac%7B%5BADP%5D%5BHPO_4%5E%7B2-%7D%5D%7D%7B%5BATP%5D%7D)
In this expression, only gaseous or aqueous states are includes and pure liquid or solid states are omitted.
Given:
= 5.0 mM
= 0.60 mM
= 5.0 mM
Now put all the given values in this expression, we get

Now we have to calculate the value of
.
The formula used for
is:
............(1)
where,
= Gibbs free energy for the reaction = ?
= standard Gibbs free energy = -30.5 kJ/mol
R = gas constant = 
T = temperature = 
Q = reaction quotient = 
Now put all the given values in the above formula 1, we get:


Therefore, the value of
is -49.6 kJ/mol
Answer:
The correct answer is - n and l.
Explanation:
The size of an orbital is determined by the principal number of shell which is represented by n. The larger the energy level (n) bigger the size of the orbital. N can be any integer value: 1, 2, 3 . . . . and so on.
l represents the angular momentum or subshell number provides the overall shape of an orbital in this subshell only integer values between 0 and n-1 are permitted.
Thus, n & l are two quantum numbers that determine the energy level of an orbital in a multielectron atom.
use variable
1K₂MnF₆ + aSbF₅⇒ bKSbF₆ + cMnF₃ + dF₂
K, left=2,right=b⇒b=2
Mn, left=1, right=c⇒c=1
Sb, left=a, right=b⇒a=b=2
F, left=6.1+5a, right=6b+3c+2d
equation:
6+5(2) = 6(2)+3(1)+2d
16=15+2d
1=2d
d=0.5
So the reaction equation becomes:
1K₂MnF₆ + 2SbF₅⇒ 2KSbF₆ + 1MnF₃ + 0.5F₂ x2
2K₂MnF₆ + 4SbF₅⇒ 4KSbF₆ + 2MnF₃ + F₂
Answer:
B
Explanation:
FUN is not building block of matter.