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melomori [17]
2 years ago
11

22 Directions: Select the correct food web. In Ottawalley National Park, grass is abundant. Gazelles spend most of the day feedi

ng on grass, their main source of food. Gazelles are hunted and eaten by the park's wild dogs. Lions are a predator of both wild dogs and gazelles. Which of the following food webs best represents the relationships described above? lion lion wild dog - wild dog gazelle gazelle grass grass lion lion wild dog wild dog gazelle gazelle grass grass​

Chemistry
2 answers:
dezoksy [38]2 years ago
5 0

Answer:

Explanation:

22 Directions: Select the correct food web. In Ottawalley National Park, grass is abundant. Gazelles spend most of the day feeding on grass, their main source of food. Gazelles are hunted and eaten by the park's wild dogs. Lions are a predator of both wild dogs and gazelles. Which of the following food webs best represents the relationships described above? lion lion wild dog - wild dog gazelle gazelle grass grass lion lion wild dog wild dog gazelle gazelle grass grass​

PilotLPTM [1.2K]2 years ago
3 0

Answer:

its the 4th one i just did it on study island

Explanation:

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Zinc reacts with hydrochloric acid according to the reaction equation Zn ( s ) + 2 HCl ( aq ) ⟶ ZnCl 2 ( aq ) + H 2 ( g ) How ma
Katen [24]

Answer: 12.0 milliliters of 6.50 M HCl ( aq ) are required to react with 2.55 g Zn.

Explanation:

moles =\frac{\text {given mass}}{\text {Molar mass}}

moles of zinc =\frac{2.55g}{65.38g/mol}=0.0390moles

The balanced chemical equation is :

Zn(s)+2HCl(aq)\rightarrow ZnCl_2(aq)+H_2(g)

According to stoichiometry:

1 mole of zinc reacts with = 2 moles of HCl

Thus 0.0390 moles of zinc reacts with = \frac{2}{1}\times 0.0390=0.0780 moles of HCl

To calculate the volume for given molarity, we use the equation:

\text{Molarity of the solution}=\frac{\text{Moles of solute}\times 1000}{\text{Volume of solution in ml}}     .....(1)

Molarity of HCl solution = 6.50 M

Volume of solution = ?

Putting values in equation 1, we get:

6.50M=\frac{0.0780\times 1000}{\text{Volume of solution in ml}}

{\text{Volume of solution in ml}}=12.0ml

Thus 12.0 ml of 6.50 M HCl ( aq ) are required to react with 2.55 g Zn

3 0
2 years ago
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prisoha [69]

Answer:

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6 0
2 years ago
The ΔHsoln is _____.
nydimaria [60]

Sometimes negative sometimes positive, your answer is B!

4 0
3 years ago
1. Related to the number of particles in a gram of
Romashka-Z-Leto [24]

Answer:

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Explanation:

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6 0
1 year ago
The temperature inside your freezer is 0 degrees Celsius. You place a balloon with an initial temperature of 30 degrees C and a
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Answer:

V=0.68L

Explanation:

For this question we can use

V1/T1 = V2/T2

where

V1 (initial volume )= 0.75 L

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V2( final volume)= ?

T2 (final temperature in Kelvin)= 273.15

Now we must rearrange the equation to make V2 the subject

V2= (V1/T1) ×T2

V2=(0.75/303.15) ×273.15

V2=0.67577931717

V2= 0.68L

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3 years ago
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