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vladimir2022 [97]
2 years ago
15

I need help with these two, can someone pls help meI need this ASAPno links pls ​

Mathematics
1 answer:
Anestetic [448]2 years ago
3 0
5x+4+8x-3=79
13x=79-1
x=6
DBC=34
ABC=45

6x+20+2x+4 = 180
8x = 156
x=19.5
TQS=137
RQS=43
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Ron walks 0.5 miles on track in 10 minutes Stevie walks 0.25 mile on the track in 6 minutes find the unit rate for each walker i
Ahat [919]

Answer:

0.5 miles/ 10 minutes* (60 minutes/ 1 hour)= 3 miles/hour.


0.25 miles/ 6 minutes* (60 minutes/ 1 hour)= 2.5 miles/hour.


The unit rate of Ron is 3 miles/hour.

The unit rate of Steve is 2.5 miles/hour.

Therefore, Ron walks faster~

Step-by-step explanation:


3 0
2 years ago
Help me on this<br> Because I don’t get it
Lady_Fox [76]

9514 1404 393

Answer:

  8x +36 = 15

Step-by-step explanation:

The fractions can be made to disappear by multiplying the equation by their least common denominator. That number is 18.

  18(4/9x +2) = 18(5/6)

  8x +36 = 15

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The solution is x = -21/8.

5 0
2 years ago
Read 2 more answers
In the equation, 6(3x+5) -4x =35 , what are some of the steps that should be taken to solve for x? Select all that apply.
Natalija [7]
You need to combine like terms and subtract 30. How you find the answer is you work the problem first 1. Distribute the 6 (18x+30)-4x=35 then 2. combine like terms 18x and -4x. (14x+30)=35 then 3. Subtract 30 from both sides (14x)=5
6 0
3 years ago
Number 6.i need full working​
Pavlova-9 [17]
You can do this on a calculator if you search up online radius and height measurement calculator.
4 0
3 years ago
The population of bacteria in a culture grows at a rate proportional to the number of bacteria present at time t. After 3 hours
ella [17]

Answer:

137

Step-by-step explanation:

Use the model A = Pe^(kt), where P is the initial number and k is the growth constant.  Then, in case 1,

300 = Pe^(k*3)

and in case 2,

4000 = Pe^(k*10).  We need to find P and e^k.

300 = Pe^(k*3) can be rewritten as (300/P) = [e^k]^3, which in turn may be solved for e^k:

∛(300/P) = e^k

Now we go back to 4000 = Pe^(k*10) and rewrite it as (4000/P) = [e^k]^10.  Substituting ∛(300/P) for e^k, we obtain:              

(4000/P) =  (300/P )^(10/3)

which must now be solved for P.  Raising both sides by the power of 3, we get:

(4000/P)^3 = (300/P)^10.  Therefore,

4000^3       300^10

------------- = -------------

   P^3             P^10

which reduces to:

4000^3       300^10

------------- = -------------

       1             P^7

or

        1         P^7

------------  =  -----------

4000^3       300^10

or:

           300^10

P^7 = ---------------- = 9.226*10^13  = 92.26*10^12

           4000^3

Taking the 7th root of both sides results in P = (92.26*10^12)^(1/7), or

                                                                        P = 137.26

The initial number of bacteria was 137.

7 0
2 years ago
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