I'm assuming the two cars start from the same point!
<span>Let's measure time t from the time when Car 2 starts. </span>
<span>Then the distances travelled by the cars up to the time of overtaking, t, must be the same. </span>
<span>And we need to measure all time in hours, so 18 mins. is 0.3 hours. </span>
<span>So, 45 x (0.3 + t) = 65 x t, so 20t = 13.5, so t = 13.5/20 = 27/40 = 40.5/60, i.e. 40 min 30 sec</span>
Surface areasphere=4pir^2
surface area cube=6pis^2 where s is the side
the side is 2r
SAcube=6pi(2r)^2=6pi4r^2=24pir^2
so sphere to cube is
4pir^2:24pir^2
divide both sides by 4pir^2
1:6
the ratio is1:6
8.722 / (-3.56)
Expand by multiplying both numerator and denominator by 1000.
Reduce the fraction to the lowest terms by extracting and cancelling out 178.
- = -2.45
Answer:
You can use this step to answer your question
Step-by-step explanation:
he vector projection of #vecu# onto #vecv# is
#=(vecu.vecv)/(||vecv||^2)*vecv#
The dot product is
#vecu.vecv=<3,15>.<-1,5>=-3+75=72#
The modulus of #vecv# is
#||vecv||=||<-1,5>||=sqrt(1+25)=sqrt26#
The vector projection is
#=72/26<-1,5> = 36/13<-1,5>#
The scalar projection is
#(vecu.vecv)/(||vecv||)=72/sqrt26#
Answer:
you can literally look these up and you get step by step answers
Step-by-step explanation: