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3 years ago

If Vector A (6,4) and Vector B is (-2, -1), what is A-B

Physics

1 answer:

tatyana61 [14]3 years ago

6 0

Answer:

$(8,5)$

Explanation:

Think of it as a simpler algebra problem with parentheses. What you are doing is $(6,4)-(-2,-1)$

so lets DISTRIBUTE this negative sign to (-2, -1)

we get: $(6,4)+(2,1)$

add the x values and add the y values

$(8,5)$

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Answer:

Following are the solution to this question

Explanation:

please find the complete question in the attached file.

In point a:

The answer is "bottom".

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$T= mg + \frac{m V^2}{2}$

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3 years ago

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Answer:

67.5

Explanation:

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The velocity can be calculated as follows

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3 years ago

A handel or knob is fixed at the free end of door. Why?

andriy [413]

Maximum torque.
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3 years ago

A .183 kg ball is moving 18.8 m/s when it runs into a spring of spring constant 86.9 N/m. How much KE does the ball have when it

Lemur [1.5K]

Answer:

The value is $KE_B = 20.59 \ J$

Explanation:

From the question we are told that

The mass of the ball is $m = 183 \ kg$

The initial speed of the ball is $u = 18.8 \ m/s$

The spring constant is $k = 86.9 \ N/m$

The compression distance is $x = 0.520 \ m$

Generally the energy stored in the string is mathematically represented as

$E = \frac{1}{2} * k * x^2$

=> $E = \frac{1}{2} * 86.9 * 0.520 ^2$

=> $E = 11.75 \ J$

Generally the kinetic energy of the ball is mathematically represented as

$KE_b = \frac{1}{2} * m * u^2$

=> $KE_b = \frac{1}{2} * 0.183 * (18.8 )^2$

$KE_b = 32.34 \ J$

Generally the KE the ball have when it has compressed the spring is mathematically represented as

$KE_B = KE_b - E$

=> $KE_B = 32.34 - 11.75$

=> $KE_B = 20.59 \ J$

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3 years ago

A car is going 60.0 mi/h and has to stop in 6.0 seconds. What is the car’s acceleration?

diamong [38]

Explanation:

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3 years ago

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