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ankoles [38]
3 years ago
7

Do electric field lines actually exist?​

Physics
1 answer:
konstantin123 [22]3 years ago
8 0

Answer: No

Explanation:they do not exist electric field lines are only imaginary

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The graph at the right shows the force needed to pull a bow back as the string is pulled further and further.
Sindrei [870]

A. 9 J

In a force-distance graph, the work done is equal to the area under the curve in the graph.

In this case, we need to extrapolate the value of the force when the distance is x=30 cm. We can easily do that by noticing that there is a direct proportionality between the force and the distance:

F=kx

where k is the slope of the line. We can find k, for instance chosing the point at x=5 cm and F=10 N:

k=\frac{F}{x}=\frac{10 N}{5 cm}=2 N/cm

And now we can calculate the work by calculating the area under the curve until x=30 cm, F=60 N:

W=\frac{1}{2} (height) (base)= \frac{1}{2}(60 N)(0.30 m)=9 J


B. 24.5 m/s

The mass of the arrow is m=30 g=0.03 kg. The kinetic energy of the arrow when it is released is equal to the work done by pulling back the bow for 30 cm:

W=K=\frac{1}{2}mv^2

where m is the mass of the arrow and v is its speed. By re-arranging the formula and using W=9 J, we find the speed:

v=\sqrt{\frac{2W}{m}}=\sqrt{\frac{2\cdot 9J}{0.03 kg}}=24.5 m/s

8 0
3 years ago
Which of the following has the strongest magnetic field?
Dahasolnce [82]
The correct answer would be the sun


7 0
3 years ago
Read 2 more answers
Which formula gives the value of velocity ratio of wheel and axle?​
aleksandrvk [35]

Answer:

measurement of force amplification

8 0
3 years ago
9. The Metro Rail makes a stop at NRG Stadium to pick up some Texans fans after the game. After
attashe74 [19]

Answer:

It takes the train 7.5 seconds to reach top speed

The train travels 112.5 meters before it reaches its top speed

Explanation:

The Metro Rail makes a stop at NRG Stadium to pick up some Texans

fans after the game

After  all the passengers board, the train accelerates at a rate of 4 m/s²

to a top speed of 30 m/s

We need to find the train takes how many seconds to reach the

top speed

Given is:

→ The train start from rest, then its initial speed u = 0

→ It acceleration a = 4 m/s²

→ Its top speed v = 30 m/s

To find the time we can use this rule;

→ t=\frac{v-u}{a}

→ t=\frac{30-0}{4}=\frac{30}{4}=7.5 seconds

<em>It takes the train 7.5 seconds to reach top speed</em>

<em></em>

Now we need to find how far the train travels before reaches top speed

We can use this rule;

→ v² = u² + 2as, where s is the distance

→ v = 30 m/s , u = 0 , a = 4 m/s²

Substitute these values in the rule

→ (30)² = 0 + 2(4) s

→ 900 = 8 s

Divide both sides by 8

→ s = 112.5 m

<em>The train travels 112.5 meters before it reaches its top speed </em>

7 0
3 years ago
What is the force of gravity between two 3.0 kg masses 1.0 m apart?
gavmur [86]

m₁ = mass of the first object = 3.0 kg

m₂ = mass of the second object = 3.0 kg

r = distance between the first and second object = 1.0 m

G = universal gravitational constant = 6.67 x 10⁻¹¹ N m²/kg²

F = force of gravity between the two objects = ?

according to law of gravitation, force of attraction "F" between two objects m₁ and m₂, placed distance "r" apart is given as

F = G m₁ m₂/r²

inserting the values

F = (6.67 x 10⁻¹¹) (3.0) (3.0)/(1.0)²

F = (6.67 x 10⁻¹¹) (9.0)

F = 60.03 x 10⁻¹¹ N

F = 6.003 x 10⁻¹⁰ N

6 0
3 years ago
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