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ankoles [38]
3 years ago
7

Do electric field lines actually exist?​

Physics
1 answer:
konstantin123 [22]3 years ago
8 0

Answer: No

Explanation:they do not exist electric field lines are only imaginary

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Three crates with various contents are pulled by a force Fpull=3615 N across a horizontal, frictionless roller‑conveyor system.
SIZIF [17.4K]

The question is incomplete. Here is the complete question.

Three crtaes with various contents are pulled by a force Fpull=3615N across a horizontal, frictionless roller-conveyor system.The group pf boxes accelerates at 1.516m/s2 to the right. Between each adjacent pair of boxes is a force meter that measures the magnitude of the tension in the connecting rope. Between the box of mass m1 and the box of mass m2, the force meter reads F12=1387N. Between the box of mass m2 and box of mass m3, the force meter reads F23=2304N. Assume that the ropes and force meters are massless.

(a) What is the total mass of the three boxes?

(b) What is the mass of each box?

Answer: (a) Total mass = 2384.5kg;

               (b) m1 = 915kg;

                   m2 = 605kg;

                   m3 = 864.5kg;

Explanation: The image of the boxes is described in the picture below.

(a) The system is moving at a constant acceleration and with a force Fpull. Using Newton's 2nd Law:

F_{pull}=m_{T}.a

m_{T}=\frac{F_{pull}}{a}

m_{T}=\frac{3615}{1.516}

m_{T}=2384.5

Total mass of the system of boxes is 2384.5kg.

(b) For each mass, analyse each box and make them each a free-body diagram.

<u>For </u>m_{1}<u>:</u>

The only force acting On the m_{1} box is force of tension between 1 and 2 and as all the system is moving at a same acceleration.

m_{1} = \frac{F_{12}}{a}

m_{1} = \frac{1387}{1.516}

m_{1} = 915kg

<u>For </u>m_{2}<u>:</u>

There are two forces acting on m_{2}: tension caused by box 1 and tension caused by box 3. Positive referential is to the right (because it's the movement's direction), so force caused by 1 is opposing force caused by 3:

m_{2} = \frac{F_{23}-F_{12}}{a}

m_{2} = \frac{2304-1387}{1.516}

m_{2} = 605kg

<u>For </u>m_{3}<u>:</u>

m_{3} = m_{T} - (m_{1}+m_{2})

m_{3} = 2384.5-1520.0

m_{3} = 864.5kg

8 0
3 years ago
What is the application of a spherometer in the medical field?​
Anton [14]

Answer:

To correct the defects of vision by measuring the radius of curvature and thus the power of the lenses.

Explanation:

A spherometer is an instrument used to measure the curvature of objects such as lenses and curved mirrors.

Generally it consists of a fine screw which is moving in a nut carried on the center of a 3 small legged table or frame. The feet forms the vertices of an equilateral triangle. The lower end of the screw and those of the table legs are finely tapered and terminate in hemispheres.

If the screw has two turns of the thread to the milli meter the head is generally divided into 50 equal parts, so that differences of 0.01 millimeter may be measured without using a vernier scale.

The spherometer is used to measure the radius of curvature of the lenses so that the opthalmologist find the focal length of the lens and then give the  power to the lens to correct the defects of vision.  

8 0
3 years ago
Which of the following quantities would be acceptable representations of weight? Check all that apply.
Oxana [17]

Only 12 lb and 1600 kN .

7 0
3 years ago
A car is stopped at a red light. When the light turns green, the car accelerates until it reaches a final velocity of 45 m/s. It
tigry1 [53]

Answer:

270 m

Explanation:

We can find the distance travelled by the car by using the following suvat equation:

s=(\frac{u+v}{2})t

where

s is the distance travelled

u is the initial velocity

v is the final velocity

t is the time

For the car in this problem,

u = 0

v = 45 m/s

t = 12 s

Substituting into the equation, we find:

s=(\frac{0+45}{2})(12)=270 m

8 0
3 years ago
A machine lifts a 44,760 newton crate 2 meters into the air in 10 seconds. How many horsepower does the machine
VladimirAG [237]

Answer:

<u>8952 W</u>

Explanation:

<u>Given</u> :

  • Force = 44,760 Newtons
  • Displacement = 2 meters
  • Time taken = 10 seconds

<u>Equation</u>

  • Power = Work / Time
  • Power = Force x Displacement / Time

<u>Solving</u> :

  • P = 44760 x 2 / 10
  • P = 4476 x 2
  • P = <u>8952 W</u>
7 0
2 years ago
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