A dynamite blast at a quarry launches a rock straight upward, and 1.7 s later it is rising at a rate of 17 m/s. Assuming air res
1 answer:
Answer:
(a)
(b)
Explanation:
We can derive the initial speed of the rock from the equation of the speed in function of the time:
Using the given values for the speed at time t=1.7s, we get:
In words, the speed of the rock at launch is 34m/s (a).
Next, we use this to calculate the speed at t=4.9s:
This means that the speed of the rock at 4.9s after the launch is 14m/s (b), and the negative sign means that it is moving downwards.
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The correct answer is
<span>force per unit charge.
In fact, the electric field strength is defined as the electric force per unit charge experienced by a positive test charge located in the electric field. In formula:
</span>
where
E is the electric field strength
F is the electric force experienced by the charge
q is the positive test charge.
<span>force per unit charge.
In fact, the electric field strength is defined as the electric force per unit charge experienced by a positive test charge located in the electric field. In formula:
</span>
where
E is the electric field strength
F is the electric force experienced by the charge
q is the positive test charge.
Answer:
Explanation:
<u>Conservation of Momentum </u>
The total momentum of a system of two particles is
Where m1,m2,v1, and v2 are the respective masses and velocities of the particles at a given time. Then, the two particles collide and change their velocities to v1' and v2'. The final momentum is now
The momentum is conserved if no external forces are acting on the system, thus
Let's put some numbers in the problem and say
120=120
It means that when the particles collide, the first mass returns at 6 m/s and the second continues in the same direction at 28 m/s
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