If a car starts from a stop, and hits 27 meters per second in 8 seconds, what is its acceleration?
1 answer:
You might be interested in
Answer:
speed of golf ball is 1.15 × m/s
and % of uncertainty in speed = 2.07 × %
Explanation:
given data
mass = 45.9 gram = 0.0459 kg
speed = 200 km/hr = 55.5 m/s
uncertainty position Δx = 1 mm = m
to find out
speed of the golf ball and % of speed of the golf ball
solution
we will apply here heisenberg uncertainty principle that is
uncertainty position ×uncertainty momentum ≥ ......1
Δx × ΔPx ≥
here uncertainty momentum ΔPx = mΔVx
and uncertainty velocity = ΔVx
and h = 6.626 × Js
so put here all these value in equation 1
× 0.0459 × ΔVx =
ΔVx = 1.15 × m/s
and
so % of uncertainty in speed = ΔV / m
% of uncertainty in speed = 1.15 × / 55.5
% of uncertainty in speed = 2.07 × %
Answer:
Speed= 6cm/s and velocity= 6cm/s in the negative direction
Explanation:
the change in position is from 45cm to 27 cm (moving towards the negative x direction)
And the change in time:
Now we must define the difference between speed and velocity:
Speed is a scalar quantity, which means that it is a number. Velocity is also a number but you must also indicate the direction of the movement.
Thus, the speed is:
An the velocity is:
6cm/s in the negative direction