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3 years ago

The word "continental" means that the air mass formed over ____________.

Chemistry

1 answer:

statuscvo [17]3 years ago

8 0

Answer:

over land is the correct ☑ answer plz mark me as brainliest

have a great day ahead

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For the reaction ? Fe+? H2o ⇀↽? Fe3o4+? H2 , a maximum of how many grams of fe3o4 could be formed from 354 g of fe and 839 g of

Evgesh-ka [11]

The given reaction is:

3Fe + 4H2O → Fe3O4 + 4H2

Given:

Mass of Fe = 354 g

Mass of H2O = 839 g

Calculation:

Step 1 : Find the limiting reagent

Molar mass of Fe = 56 g/mol

Molar mass of H2O = 18 g/mol

# moles of Fe = mass of Fe/molar mass Fe = 354/56 = 6.321 moles

# moles of H2O = mass of h2O/molar mass of H2O = 839/18 = 46.611 moles

Since moles of Fe is less than H2O; Fe is the limiting reagent.

Step 2: Calculate moles of Fe3O4 formed

As per reaction stoichiometry:

3 moles of Fe form 1 mole of Fe3O4

Therefore, 6.321 moles of Fe = 6.321 * 1/ 3 = 2.107 moles of Fe3O4

Step 4: calculate the mass of Fe3O4 formed

Molar mass of Fe3O4 = 232 g/mol

# moles = 2.107 moles

Mass of Fe3O4 = moles * molar mass

= 2.107 moles * 232 g/mol = 488.8 g (489 g approx)

7 0

3 years ago

Read 2 more answers

Can you tell me answe of all (5,6,7,8)

GREYUIT [131]

Answer:

i dont know thank you soo much

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1 year ago

A student prepared a stock solution by dissolving 20.0 g of NaOH in enough water to make 150. mL of solution. She then took 15.0

pav-90 [236]

Answer:

$0.769\ \text{M}$

Explanation:

Mass of stock solution = 20 g

Molar mass of NaOH = 40 g/mol

Volume of stock solution = 0.150 mL

$M_2$ = Concentration of NaOH for the final solution

$V_1$ = Amount of stock solution taken = 15 mL

$V_2$ = Total volume of solution = 65 mL

Molarity is given by

$M_1=\dfrac{\text{Mass}}{\text{Molar mass}\times \text{Volume}}\\\Rightarrow M_1=\dfrac{20}{40\times 0.15}\\\Rightarrow M_1=\dfrac{10}{3}$

We have the relation

$M_1V_1=M_2V_2\\\Rightarrow M_2=\dfrac{M_1V_1}{V_2}\\\Rightarrow M_2=\dfrac{\dfrac{10}{3}\times 15}{65}\\\Rightarrow M_2=0.769\ \text{M}$

The concentration of NaOH for the final solution is $0.769\ \text{M}$ .

5 0

3 years ago

How to do question no 17

Tcecarenko [31]

Explanation:

even I don't know this answer

but maybe you can solve it by putting the formula

4 0

3 years ago

A titration is performed on a 25.0 mL sample of calcium hydroxide. A volume of

slamgirl [31]

Answer:

$\boxed {\boxed {\sf 0.28 \ M}}$

Explanation:

Titration is a method used to determine the concentration of a substance. The formula for this is:

$M_AV_A= M_BV_B$

Where M is the molarity of the acid or base and V is the volume of the acid or base.

We know that 46.0 milliliters of a 0.15 molar solution of nitric acid wereused in the titration. 25.0 milliliters of solution of calcium hydroxide of unknown molarity were also used.

$\bullet \ M_A= 0.15 \ M \\\bullet \ V_A= 46.0 \ mL\\\bullet \ V_B= 25.0 \ mL$

Substitute these known values into the formula.

$0.15 \ M * 46.0 \ mL= M_B * 25.0 \ mL$

We are solving for the molarity of the base, so we must isolate the variable $M_B$ . It is being multiplied by 25.0 milliliters. The inverse operation of multiplication is division, so we divide both sides of the equation by 25.0 mL.

$\frac {0.15 \ M * 46.0 \ mL}{25.0 \ mL}= \frac{M_B * 25.0 \ mL}{25.0 \ mL}$

$\frac {0.15 \ M * 46.0 \ mL}{25.0 \ mL}= M_B$

The units of milliliters (mL) cancel.

$\frac {0.15 \ M * 46.0 }{25.0}=M_B$

$\frac {6.9}{25.0 } \ M =M_B$

$0.276 \ M = M_B$

The original measurements have 2 or 3 significant figures. We always round our answer to the least number of sig figs, which is 2. For the number we calculated, that is the hundredths place. The 6 in the thousandths place tells us to round the 7 up to an 8.

$0.28 \ M \approx M_B$

The concentration of calcium hydroxide is approximately <u>0.28 M.</u>

6 0

3 years ago