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3 years ago

How test berween nitric and sulferic acid?

1 answer:

7 0

Ba(OH)₂(aq) + 2HNO₃(aq) = Ba(NO₃)₂(aq) + 2H₂O(l)
At the reaction of barium hydroxide with nitric acid there are no visual changes.

Ba(OH)₂(aq) + H₂SO₄(aq) = BaSO₄(s) + 2H₂O
At the reaction of barium hydroxide with sulfuric acid the precipitat of white color is formed.

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When aqueous solutions of sodium acetate and hydrobromic acid are mixed, an aqueous solution of sodium bromide and acetic acid r

timofeeve [1]

CH3COONa+HBr ----> NaBr + CH3COOH
CH3COO⁻ +H⁺ ------> CH3COOH , because CH3COOH is a weak acid

3 0

3 years ago

Read 2 more answers

What is the relationship between the reactant and yield

solong [7]

Yield is the measured amount of a product obtained from a reaction.

Hope that's helpful

7 0

4 years ago

Draw the condensed structural formula in the equation for the saponification of trimyristin with koh

Ludmilka [50]

Explanation: Saponification reaction is a reaction in which hydrolysis of fats takes place under basic conditions giving glycerol and a salt of corresponding fatty acid.

We are given a Fatty acid called as Trimyristin.

Its reaction with KOH leads to the formation of soap and is given by the equation:

$Trimyristin+3 KOH\rightarrow Glycerol+Soap$

$C_{45}H_{86}O_6+3KOH\rightarrow C_3H_5(OH)_3+3CH_3(CH_2)_{12}CO_2K$

The condensed structural formula for the equation is given in the image attached.

4 0

3 years ago

Read 2 more answers

P4O10 -> 4P+5O2 How many moles of phosphorus would be produced if 5.3 mol of P4O10 reacted?

viktelen [127]

Answer:

21.2 moles.

Explanation:

Hello!

In this case, for the given chemical reaction, we can see there is a 1:4 mole ratio between tetraphosphorous decaoxide and phosphorous; therefore, the following proportional factor provides the requested moles of phodphorous:

$n_P=5.3molP_4O_{10} *\frac{4molP}{1molP_4O_{10}} \\\\n_P=21.2molP$

Best regards!

5 0

3 years ago

Imagine you were doing a calorimetry experiment to measure the molar enthalpy change for dissolving ammonium chloride (NH4Cl(s))

Bess [88]

Answer:

Volume of water

Initial temperature of the solution

Final temperature of the solution

Mass of NH₄Cl

Explanation:

There are two heat transfers involved in this experiment.

Heat of solution of NH₄Cl + heat lost by water = 0

q₁ + q₂ = 0

nΔH + mCΔT = 0

nΔH = -mCΔT

ΔH = -mCΔT/n

So, you must measure

the volume of water (you will probably use its density to calculate its mass)
the initial and final temperatures of the solution (to calculate ΔT)
the mass of NH₄Cl (to calculate the number of moles)

You will probably assume that the specific heat capacity of the solution is the same as that of water, so you won't be measuring it.

4 0

3 years ago